Question
Asked Oct 1, 2019
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I can't find the limit.

(-4x26y2)
lim
(z,)(0,0)
4æ2 + 6y2 + 1) - 1
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(-4x26y2) lim (z,)(0,0) 4æ2 + 6y2 + 1) - 1

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Expert Answer

Step 1

Obtain the value of li...

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(-4x2+6y2) (-4х? +бу? +1) +1 (-4x2 +6y?) -4x2+6y' +1)-1 (- lim (xv)(0,0) lim -4x2 6y2 +1) +1 -4x2612 1)-1 (0,0) _ (-4х* + бу?)(- lim (-4x? + бу? +1) +1 (4x? + буз +1) -1 xy)0,0) (-4x26y2)j(-4x2 +6y +1)+1 lim = (4x* +бу?) (х,у)—0,0) -4х? + бу? +1) +1 lim (xy)(0,0) V (-4(0) +6(0)+1)1 =2

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