4y- 5 4) y2 - 25

Q: ² = 3x² + 3y², x = 0, y = 0, z = 2

A: Solution

Q: 2e-u²+2 +2 dydz. 1

A: We have to evaluate the integral ∫01∫1u2e-u2+2dydz

Q: Solve the system.

A: Given: 3x+y-2z=-1          2x-3y+z=4 4x+5y-z=-2 The solution of the given system of equations can…

Q: Questionzi y²-ZY-% yzt 51-36

A: The given expression,     y2-2y-8y2+5y-36

Q: + 2n + 3, a, = 4 3D4 1 7-1:0=3.

A:

Q: 1 26. zp- (z+1)° (2z² +4z–34)

A:

Q: 2x+4 %3D の 4 6. %3D 41-

A: Solution is given below:

Q: у" + 2хy' 3 х — 2у, У (0) %3D 2 & y'(0) = 5 -

A:

Q: 5-y" 2y + 4y= 0; y(0) = 2, y(0) = 0

A:

Q: 6. If x = 2 and y =-3, what is the value of 2r-3ry-2y?

A: Given x=2 and y=-3We need to find the value of 2x2-3xy-2y2

Q: 4-a2 8-a2-y2 (2² + y²) dzdydx 2

A: Given ∫-22∫04-x2∫x2+y28-x2-y2(x2+y2)dzdydx Change the integral into cylindrical coordinates

Q: Evaluate: ,(3y – 8y* + 9y²)dy | -2

A: let I = ∫-223y6-8y4+9y2dywe know that ∫-aaf(t)dt = 2∫0af(t)dt

Q: 6y'' + 5y" + y' = 0 y(0) = -2, y'(0) = 2, y'"(0) = 0 %3D

A:

Q: 1+4) 20-y %3D 2.

A: To find the value of y.

Q: 2. y" - Зу' +2у %3D е** + 6х3 — 2+ 3sin(4x)

A:

Q: Зх + Зу + 12z %3 6 4z = 2 x + y + 2х + 5y + 20z 10 —х + 2у + 8z = 4 (х, у, 2) 3D

A:

Q: 3.2 X(x²-1)-y=xy* ;y(2)=-

A:

Q: 14メナ2y=7 X-y=4

A: x + 2y = 7 ..... (i) x - y = 4 ...... (ii)   (i) - (ii) gives, (x+2y) - (x-y) = 7 - 4 So, 3y = 3 So,…

Q: 6. 3x + y 2 9 2x +4y 2 16 x, y 2 0

A: I have solve only #6 as you have only asked for it

Q: ý +4ý + 3y Y6) = y'(0) = 1 %3D to

A: Given that

Q: 1. y = - V2x +1 2. y = (x – 1)3 + 2 3. y =-1 2x 4. y? = 6– x 5. y = 1- |x|

A:

Q: 7) y"+4y+20y-23sint-15cost y(0)-0, y'(0)--1

A: We have to solve given problem:

Q: 13. x" = -2x + 2y, y" = 2x - 5y; x(0) = 2, x ' (0) = 3, y(0) = 1, y' (0) = 2

A:

Q: 9x-y+z=3 10x-y+z=8 Find (x,y,z)

A:

Q: HW: Expand (4+ y 2- (a-5) 1-

A: I have used binomial expansion

Q: 2 y + = = -8, x – 2y – 3: = 0, х - - 3 : -х+у+2:%3D3.

A:

Q: 8. y = x2(x + 1)3 9. (2 x- 1)' (x+ 3)* 10. y=5 x- 3 11, s 3 V16+ KIDA

A:

Q: 3y +5 (5y-7)2 dy

A: We can find the integration as below.

Q: 10 dS (3t2-12t-15)dt %3D

A:

Q: 8. 2y" – 2y' + y = 0; y(0) = –1,y'(0) = 0

A:

Q: у' %— х — 4у, when x %3D 2,у 3 3 y' — х — 2усot 2x

A:

Q: (4) y" + 6y' + 10y = 20x + 22; y (0) = 2, y'(0) = -2 %3D

A:

Q: 18y - 17 dy 3/2

A: Topic = Integration   Formula used∫x dx = xn+1n+1+C

Q: 12e* 10) y"-2y'+y =-

A:

Q: ∫(4y-3)(16y^2+12y+9)dy

A:

Q: 4y" +5y'+3y = 0, y(0) = -1, y' (0) = 1

A:

Q: O 2y=-4x+10 O 2y+x=10 O y+2x=-5 O 2y=-10x-4

A:

Q: 4. xy-4z2 = -7; P(-3, 1, –2) %3D

A: According to the guideline we should have been able to solve only one question at a time

Q: -3 8x°y² ' 12x'y* 6.,2 4 17m m m+5 5х-2 13 - x(x-7)

A: To find the LCD

Q: show the complete solution using differential equation

A: As per the guidelines we can solve 1 part only

Q: 1) y" – 10y' + 25y = 8e- y(0) = 1, y'(0) = -4;

A: Follow the steps.

Q: 14. x = -y + 4y, x = 0 3 1 1 2 3 2.

A: Consider

Q: 9. 2(x + y) 25(x-y') at (3, 1)

A:

Q: 3) y=--x - 1 | 1 y =-x-4 4 Ay 5 4 3 -2 -2 -3 Answer:

A: follow the  next step

Q: -. х— 2у %3D —4 -x+ y = 2 с. Зх + 15у %3D 12 *+y = 1 х 5 1 x +-y = 3 2

A:

Q: 8y" – 10y' + 3y= 0, y(0) = 2, y'(0) = 1

A:

Q: 1. y ax + bx²,

A: As tou you have asked for question number 1 only,  then it solved by the method of formation of…

Q: %24 2) y= 2Vx+1 %3D 9- 9- レーメ Ay 3/ 1) y%=

A: Topic = Functions

Q: 23. y = 2x, y=x, 0<x< 6

A:

Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.