4z (z-1)(z-2) integrate easily, but only do the partial fraction decomposition (do not find any antiderivatives). Here we will decompose the expression into partial fractions. This is broken into steps below. The goal here is to create a partial fraction decomposition that we COULD 1. What is the form of the partial fraction decomposition? Hint: the denominators will be expressions in , but the numerators will also contain unknowns other than a, that is, A, B, C etc. You may do either the convenient value or collecting coefficient methods (or a combo) like was done in the lecture video. 2. Set the form from question 1 equal to the original expression and solve for the unknowns, A, B, C etc. 4z 3. Make your final statement. What is the partial fraction decomposition of ? (z-1)(z–2)²

4z (z-1)(z-2) integrate easily, but only do the partial fraction decomposition (do not find any antiderivatives). Here we will decompose the expression into partial fractions. This is broken into steps below. The goal here is to create a partial fraction decomposition that we COULD 1. What is the form of the partial fraction decomposition? Hint: the denominators will be expressions in , but the numerators will also contain unknowns other than a, that is, A, B, C etc. You may do either the convenient value or collecting coefficient methods (or a combo) like was done in the lecture video. 2. Set the form from question 1 equal to the original expression and solve for the unknowns, A, B, C etc. 4z 3. Make your final statement. What is the partial fraction decomposition of ? (z-1)(z–2)²

Name: 4z²Here we will decompose the expressioninto partial fractions. This
Uploaded: 2024-03-20T06:38:58.000Z
Channel: Bartleby
Description: 4z²Here we will decompose the expressioninto partial fractions. This is broken into steps below. The goal here is to create a partial fraction decomposition that we COULD(z-1)(z–2)?integrate easily, but only do the partial fraction decomposition (do