# 5) Part 1Calculate the pH at the stoichiometric point when 25 mL of 0.10 M pyridine is titrated with 0.32 M HCl.

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5) Part 1

Calculate the pH at the stoichiometric point when 25 mL of 0.10 M pyridine is titrated with 0.32 M HCl.

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Step 1

Pyridine ( a weak base) reacts with HCl ( a strong acid ) to undergo neutralisation reaction to form pyridinium chloride.The balanced chemical equation goes as:

Step 2

At stoichiometric point, the acid and the base gets neutralised completely. Thus, the solution remaining is a salt solution in which the salt undergoes hydrolysis. The pH of a salt solution of a weak base and strong acid is given by the expression:

Step 3

pKb = -log Kb is a measure of the strength of the base. Its value is not mentioned, I am solving the problem, taking the general value of pKb for...

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