Question
Asked Oct 2, 2019
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I am told to solve an inequality and express the solution as an interval.

The expression:

0<=4-1x/3<2

I have attached my solution to this post. The answer I gave was:

(-inf,12]

I got half credit, but am unsure what I did wrong.

5. (2.6 #35) Solve the inequality 0$4-
and express the solution as an interval.
0E4-3x2
o 4-3x
f-gx
064-30)243
oX2 12
0k4-243
h-27XM
"12 x
04-6(a)42
-2.-3
(2)
t1
+3
help_outline

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5. (2.6 #35) Solve the inequality 0$4- and express the solution as an interval. 0E4-3x2 o 4-3x f-gx 064-30)243 oX2 12 0k4-243 h-27XM "12 x 04-6(a)42 -2.-3 (2) t1 +3

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Expert Answer

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1 Rating
Step 1

The given expression is:

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Step 2

 

If a ≤ u < b, then a ≤ u and u < b : using this inequality in the given inequality

 

04-x2
1
04
1
and 4-
x<2
3
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04-x2 1 04 1 and 4- x<2 3

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Step 3

From the left...

4x 20
1
--x-4 20-4
1
x2-4
3
1
-x<4
x12
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4x 20 1 --x-4 20-4 1 x2-4 3 1 -x<4 x12

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