5. A car sits in an entrance ramp to a freeway, waiting for a break in the traffic. The driver accelerates with constant accelerationalong the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 22m/s when it reaches theend of the 120-m-long ramp(a) What is the acceleration of the car?(b) How much time does it take the car to travel the length of the ramp?(c) The traffic on the freeway is moving at a constant speed of 20 m/s. What distance does the traffic travel while the car is movingthe length of the ramp?а

Question
Asked Oct 10, 2019
5. A car sits in an entrance ramp to a freeway, waiting for a break in the traffic. The driver accelerates with constant acceleration
along the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 22m/s when it reaches the
end of the 120-m-long ramp
(a) What is the acceleration of the car?
(b) How much time does it take the car to travel the length of the ramp?
(c) The traffic on the freeway is moving at a constant speed of 20 m/s. What distance does the traffic travel while the car is moving
the length of the ramp?
а
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5. A car sits in an entrance ramp to a freeway, waiting for a break in the traffic. The driver accelerates with constant acceleration along the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 22m/s when it reaches the end of the 120-m-long ramp (a) What is the acceleration of the car? (b) How much time does it take the car to travel the length of the ramp? (c) The traffic on the freeway is moving at a constant speed of 20 m/s. What distance does the traffic travel while the car is moving the length of the ramp? а

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check_circleExpert Solution
Step 1

Given:

Initial velocity of the car = 0 m/s

Final velocity of the car = 22 m/s

Length of the ramp = 120 m

Step 2

(a) Calculating the acceleration of the car:

Using third equation of motion, a
2s
120 m
Substitute v 22 m/s, u 0 m/s and s
(22)2 -02
2x120
2.02m/s
240
a =
2m/s2
a =
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Using third equation of motion, a 2s 120 m Substitute v 22 m/s, u 0 m/s and s (22)2 -02 2x120 2.02m/s 240 a = 2m/s2 a =

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Step 3

(b) Calculating the time taken by the car...

V-u
Using first equation of motion
a
Substitute v 22 m/s, u 0 m/s and a 2 m/s2
22m/s-Omls11s
2m/s
t 11s
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V-u Using first equation of motion a Substitute v 22 m/s, u 0 m/s and a 2 m/s2 22m/s-Omls11s 2m/s t 11s

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