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Asked Dec 17, 2019
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I need help trying to find the interval of convergence for the derivative of the series

5. Find the intervals of convergence for f,f',\f
.
f(x) = (-1)"+1 (x– 1)"+1
n+1
8.
(a) ƒ(x)= E(-1)"*1
%3D
0.
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5. Find the intervals of convergence for f,f',\f . f(x) = (-1)"+1 (x– 1)"+1 n+1 8. (a) ƒ(x)= E(-1)"*1 %3D 0.

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Expert Answer

Step 1

For the given series first find the derivative of ‘f’ in order to find the interval of convergence for the first derivative of ‘f’. The derivative is calculated as.

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n+1 (x-1)*1 n+1 f() - Σ-)κ-) п+1 (n+1)(x– 1)" n+1 f (x)= É(-1) n+1 n+1 -Σ-1) ( - 1),

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Step 2

The nth term of this serie...

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а, %3 (-1)"" (х - 1)° n+1

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Math

Calculus