5. Use 2- step substitution tan 4x sec² (4x) dx

Q: 6x sec(x) tan(x)dx

A:

Q: Find [10] -t sin(v3t) е (а) L (b) L-- [tan-1 ))

A: We have to solve given problem:

Q: 6 tan (10x) dx

A:

Q: 22. Evaluate S tanºx sec² x dx

A:

Q: S sec²(4x)(3 – tan(4x))³dx

A: Given integral is ∫ sec24x3-tan4x3dx.

Q: 1 sec²x + tanx %3D tanx tanx

A:

Q: Evaulate the intergral: ∫−10sec^2(x)tan(x)dx

A: Consider the given integral:

Q: -sin(4x²) = dx

A:

Q: Transforming dx using miscellaneous substitution will yield to secx + 1

A:

Q: 2 S tan"(3x 1)sec (3x 1)dx - |

A:

Q: Evaluate tan (7x+1) sec³(7x+1) dx .

A:

Q: 6. sech(4x) tan (4x) dx

A: We need to evaluate integral.

Q: 1) S secs 3x tan 3x dx

A:

Q: - Se-3x sin 4x dx

A:

Q: 5. tan° x sec x dx

A:

Q: 4. tan'x seczx dx

A: To find: The integral of ∫tan7x·sec32xdx. Formula used: Power rule of integration: ∫xndx=xn+1n+1+C…

Q: #4 tan lun sec x dx 4.

A:

Q: 3. y= (sec ³x + tan ²x)

A: Topic:- application of derivatives

Q: S sec²(3 – 2x)dx

A: ∫sec23-2x dx Put, 3-2x=t⇒0-21=dtdx⇒-2 dx=dt⇒dx=-dt2

Q: S 4 sec(x) tan(x) dx

A: We will use standard formula here

Q: Evaluate tan (3x+1) sec³(3x+1) dx

A:

Q: Evaluate ∫ 3x2 sin(x3) dx.

A: To evaluate the integral  ∫3x2 sinx3 dx

Q: ) ㅠ S tan5 (2x) sec² (2x) dx 2

A:

Q: 1. Evaluate 4 (sec²x tan²x ). dx

A: Use product rule of differentiation du·vdx=vdudx+udvdx. Use chain rule of differentiation…

Q: 1. Evaluate (sec²x tan²x ). dx

A: To find dsec2x tan2xdx Given function is y=sec2x tan2xwe know that, sec2x =1+tan2xthen…

Q: tan' x sec x dx 3

A:

Q: sec(tan(2x)) – 4 6. dx (cos(2x))? 8. / e*-* dx T e3x-e3x

A:

Q: Ssec*x (Vtan²x + 1) 2. 4 sec' x tan3, dx

A:

Q: Evaluate ſ tan2 2x sec 2x dx 4

A:

Q: S tan° 4x seco 4x dx а.

A:

Q: tanx * In(secx) dx

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Q: Differentiate: y = 5 tan? (25x) O y' = 750a? tan(25a³) sec2 (25a) O y' = 7502 tan? (25a) sec(25a*) O…

A:

Q: 2) Evaluate: |x sin5x dx

A: The integration of xsin5x.

Q: (tan 2x + cot 2x)² dx x2 + 2x dx 3+ 3x² +1

A:

Q: 11. y = tan e³x + etan3x

A: We can find y' as below.

Q: sec x tan x dx 9+4se ²x 2.

A: We have to evaluate the integral: ∫sec x tan x9+4 sec2 xdx Solving the given integral by…

Q: 19. Evaluate using u-substitution: S tan6x sec² x dx

A:

Q: Evaluate tan (7x + 1) sec³(7x +1) dx -

A:

Q: 2) [ tan' (-) sec" () dx , 3) | 3) T5x+4 dx, 1) sin-1x dx , tan () sec? V5x +4

A: Since the question contains multiple part we can solve only first 3 for you. If you want any…

Q: 8 tan (x) sec (x) dx

A:

Q: Number 17

A: First we break sin^3 x in sin^2x*sin x, and then we replace sin^2 x by 1-cos^2 x.THen in the next…

Q: tan 2x sec' n²2x sec 2x dx

A: Evaluate: ∫tan22xsec52xdx

Q: 1- (secx+ tanx)² dx 3x-7 dx 2- Jx-1)(x-2)(x-3)

A:

Q: |tanx dx = -In/secx|+C A In/secx + C B In/cscx +C .C -In/cscx +C D

A:

Q: Evaluate | tan (5x +1) sec³(5x+1) dx

A: We will start with the substitution, cos(5x+1) = t  And proceed as follows :

Q: (B) Evaluate tan°(3x +1) sec³(3x +1) dx

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Q: Please determine Į In(x2 + 1) dx.

A: The objective is to evaluate the integral.

Q: 2. S[ tanx- Secx]

A:

Q: Sec tan (5x) dx

A:

Q: Evaluate sec x dx /In(sec x + tan x)

A: