  5.What is the hybridization of the oxygen atoms in SO2?airs of electrons are in the o-framework ofa. Sulfur dioxide, SO2, has a total of 9 pairs of electrons. How many pSO2?b. How many bonding π electrons are there?c. How many non-bonding π electrons are there?d. How many electrons are there on either terminal atom that are not shared with the central atom?e. How many electrons are there on the central atoms that are not shared with the terminal atoms?f. How many electrons that are shared with the central and terminal atoms?

Question

Can you please help me solve all parts of this problem? (5 a, b, c, d, e, and f)? help_outlineImage Transcriptionclose5. What is the hybridization of the oxygen atoms in SO2? airs of electrons are in the o-framework of a. Sulfur dioxide, SO2, has a total of 9 pairs of electrons. How many p SO2? b. How many bonding π electrons are there? c. How many non-bonding π electrons are there? d. How many electrons are there on either terminal atom that are not shared with the central atom? e. How many electrons are there on the central atoms that are not shared with the terminal atoms? f. How many electrons that are shared with the central and terminal atoms? fullscreen
Step 1

Hybridization of oxygen atom in SO2:

The number of valence electrons in sulfur is 6

The number of valence electrons in oxygen is 6

Calculate the total valence electrons. If the value lies between 9 and 56, divide by 8 and find the first quotient (Q1). Divide the remainder (R1) by 2 and find the second quotient (Q2). Add the quotients and the final remainder (R2)

The obtained value corresponds to the type of hybridization.

Step 2

The hybridization of central atom sulfur is sp2 and each of the oxygen atom has the same hybridization sp2

Step 3

(a)

The structure of sulfur dioxide shown in figure 1.

We know that, two electrons or one pair of electron equals to one bond. Since there are two sigma...

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