5.00 cm andb = 23.0 cm. (Indicate the directionFind the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a =with the sign of your answer. Assume that the positive direction is counterclockwise.)N m10.0 N30.012.0 N9.00 N

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Asked Nov 5, 2019
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5.00 cm andb = 23.0 cm. (Indicate the direction
Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a =
with the sign of your answer. Assume that the positive direction is counterclockwise.)
N m
10.0 N
30.0
12.0 N
9.00 N
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5.00 cm andb = 23.0 cm. (Indicate the direction Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = with the sign of your answer. Assume that the positive direction is counterclockwise.) N m 10.0 N 30.0 12.0 N 9.00 N

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Expert Answer

Step 1

Given,

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Inner radius, a 0.05 m Outer radius,b-0.23 m 10 N F 12 N 0 30°

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Step 2

Torque is a twisting force that acts due to force acting at a perpendicular force from fixed point. All the forces acting on the body has been shown below,

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Step 3

As F3sinƟ component of F3 passes through point O so this cannot produce any twisting force so net torque acting on point O will be due ...

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т. -кxb(сw)+қxь(сw)+К, сов 0ха(Аси) т. 3-Вxb- Еxb+Еcos@xa

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