58. What volume of 0.0665 M KMnO4 is necessary to con vert 12.5 g KI to Ik in the reaction below? Assume that H_SO, is present in excess. 2 KMnO410 KI + 8 H2SO4 6 K2SO2 MnSO4 +5 28 H0

Q: .What volume of 0.2963 N H2SO, is required to prepare 250. 0 mL of 0.1000 N H2SO4?

A: Hey since you have posted multiple questions we will answer first question only . In case you want…

Q: Calculate the volume in (mL) required to prepare 50.0 ml that are 0.0535 M in NO, Trom a 7.88%(w/w)…

A: The question is based on the concept of molarity.    it is defined as number of moles of solute…

Q: 75 ml of an aqueous solution of HCIO4 with the percent by mass 35 % and density 1.67 kg/L , was…

A: It is given that 75 mL of an aqueous solution of HClO4 with a density of 1.67 kg/L, is mixed with…

Q: According to the reaction below, how many grams of precipitate will be produced from12.39 mL of…

A: The balanced chemical equation is as given below:-  3CaCl2(aq)   +   2Na3PO4(aq)   -------->…

Q: 19. What volume of 0.246 M HNO3 solution os reqiored tp react completely with 38.6 mL of 0.0515 M…

A: Concentration of HNO3 = 0.246 M Concentration of Ba(OH)2 = 0.0515 M Volume of Ba(OH)2 = 38.6 mL

Q: Consider the reaction of a 20.0 mL of 0.220 M C5H5NHCl (Ka = 5.9*10-6) with 12.0 mL of 0.215 M CsOH.…

A: Given: Concentration of C5H5NHCl = 0.220 M Volume of C5H5NHCl solution = 20.0 mL = 0.020 L…

Q: A KO B. CH. C co, D. P,O, 02 How many grams of Ca(OH), are required to neutralize 1000 L of 0…

A: Oxidation can be defined as the process of loss of electrons and reduction is a process of gain of…

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A:

Q: If you take a 45.0 mL portion of 1.85 M. NH3 stock solution and dilute it to a total volume of 1.85…

A: Molarity before dilution = 1.85 MVolume before dilution = 45 mLVolume after dilution = 1.85 L = 1850…

Q: 2 MnO4 + 5 H2O2(aq) + 6 H*(aq) → 2 Mn²*(aq) + 5 O2(g) + 8 H20(1) For the reaction, a 0.9339 g sample…

A: Given data, Volume of KMnO4 =15.24 mL Molarity of KMnO4 =15.24 mL

Q: 2. Calculate the percentage of MnO, in a mineral specimen if the l2 liberated by a 0.1267-g sample…

A:

Q: 2. If 665 mL of a 0.875 M KBr solution are boiled gently to concentrate the solute to 1.45 M, what…

A: In this question, we have to find out the correct answer of given problem by the help of Molarity…

Q: 0.0140 M

A:

Q: What volume (in mL) of 0.250 M nitric acid (HNO3) is needed to react with 44.8 mL of 0.150 M Na2CO3…

A: In this question, we want to determine the volume of HNO3 in mL. You can see steps how to calculate…

Q: A 0.7875 -g portion of manganese dioxide (MnO2, MW 86.94 g/mol) was added to an acidic solution in…

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Q: Consider the following reaction: Li2S(aq)+Co(NO3)2(aq)→2LiNO3(aq)+CoS(s) What volume of 0.140…

A: Given chemical equation :: Li2S(aq) + Co(NO3)2(aq)→2LiNO3 (aq) + CoS(s)

Q: A mineral was collected and weighed to be 15.001 g. The CrO4 content was determined by using  35.77…

A: Introduction :  The w/w are concentration terms used for expression the concentration of components…

Q: Q1- Calculate the percentage of SnO2 (FW = 150.7 g/mol) in a 1.2362 g sample containing Sn, if the…

A: As per the given balanced equation, 1 mol of Cr2O72- is required for 3 mol of Sn2+

Q: the following balanced reaction: Pb(NO3)2(aq) + 2KI(aq) → PbI2(s) + 2KNO3(aq) 10.9 g of KI react…

A: Consider the given information is as follows; Mass of KI reacts = 10.9 g Concentration of PbNO32…

Q: Suppose 60.0 mL of 0.10O M Pb(NO3)2 is added to 30.0 mL of 0.150 M KI. How many grams of Pbl, will…

A:

Q: A 0.308 N oxalic acid (MW 90g/mole) contains 1.386 grms of the solute. O True False

A: As we know, Normality=  number of gram equivalence of  solute present in  one liter solution…

Q: 2B. How many grams of solid Ca3(PO4)2 (310.2 g/mol) will be formed when exactly 1.826 g of CaCl2…

A:

Q: 3. (a) If 10.0 mL of H,SO4 (sp. Gr. 1.50, containing 48.7% of combined SO3 by weight 400 mL, what is…

A: Given Conditions → Volume of the Sulphuric Acid solution =10 ml. Specific Gravity = 1.5 :: Specific…

Q: A sample of ore containing Technetium weighed (4.470x10^3) g. This sample was heated in a solution…

A: Given:Molar mass of Tc(No3)3=284.03 g/molMolar mass of Tc2S3=292.20g/molMolar mass of Tc= 98.00…

Q: Consider the reaction: Part A 2K3PO4 (aq) + 3NiCl2 (aq)→Nİ3 (PO4)2(s) + 6KC1(aq) What volume of…

A: Potassium phosphate reacts with nickel chloride to form nickel phosphate and potassium chloride. The…

Q: If you have 125.0 mL of 0.01000 M KMnO4 solution, what volume (in mL) of 0.03417mol/L Fe(NO3)2…

A: The balanced reaction taking place is given as, => 5 Fe2+ + MnO4− + 8 H+ → 5 Fe3+ + Mn2+ + 4 H2O…

Q: What concentration of ClO3 results when 675 mL of 0.319 M AgCIO, is mixed with 887 mL of 0.801 M…

A: Concept:  Upon mixing the solution the concentration depends on the final solution volume and the…

Q: how many grams of precipitate will be produced

A:

Q: Phosphoric acid can be prepared from phosphorus triiodide according to the reaction: Pl3 (s) +…

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Q: Suppose 60.0 mL of 0.100 M Pb(NO3)2 is added to 30.0 mL of 0.150 M KI. How many grams of Pbl2 will…

A: The step wise solution for the calcukation of mass of PbI2 formed is -

Q: 2. A solution of ethanol (d = 0.795 g/mL) and water (H,O) is prepared by placing 30.0 mL of ethanol…

A: 2a. Data given, Density of ethanol = 0.795 g/mL  Volume of ethanol = 30.0 mL  V = volume of the…

Q: Solution X containing 0.020 mol of iron(II) sulfate requires 22.5 mL of potassium manganate(VII) for…

A: Given, The number of moles (n)= 0.020 mol The volume of KMnO4 (V)=22.5 mL=0.0225 L

Q: An aqueous mono-protic acid, with a concentration of 0.340 M was taken and 110. ml of this acid was…

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Q: 16.792 g of Ba(OH)2 (171.342 g.mol') is weighed out and carefully dissolved to make a 500.00cm…

A:

Q: A 0.3654 g sample containing only NaCI (FW=58.44 g/mol) and NaBr (FW=102.89 g/mol) was dissolved in…

A: Given: 0.3654 g sample containing only NaCI (FW=58.44 g/mol) and NaBr (FW=102.89 g/mol) was…

Q: A solution of HNO3 is standardized by reaction with pure sodium carbonate: 2H+ + Na2CO3 → 2Na+ + H2O…

A:

Q: 2 MnO4 + 5 H2O2(aq) + 6 H*(aq) → 2 Mn²*(aq) + 5 O2(g) + 8 H2O(1) For the reaction, a 0.8921 g sample…

A: Since moles of KMnO4 required = molarity X volume in L volume in L = 15.93 / 1000 = 0.01593 L…

Q: How many milliters of a 3.0 M H3PO4 solution are required to react with excess zinc to form 145g of…

A: Balanced chemical equation: 2H3PO4  +   3Zn  ------> Zn3(PO4)2   +    3H2 Form the above balanced…

Q: 16.) 0.300 moles of sodium nitrite are needed for a reaction. The solution is 0.450 M. How many mL…

A: "Since there are multiple questions and it is not mentioned that which one has to be solved so I am…

Q: 16.792 g of Ba(OH)2 (171.342 g.mol') is weighed out and carefully dissolved to make a 500.00cm³…

A:

Q: Suppose 60.0 mL of 0.100 M Pb(NO3)2 is added to 30.0 mL of O.150 M KI. How many grams of Pbl, will…

A:

Q: CzH6 CI pO, log) NAOHG)-> GHy(g)+ NaCI Cag)+ H,POu 9. 26 added 33.0q soled NaOtH 40.00 L Of to 0.017…

A: According to the mole concept, in terms of mass, the amount of substance in moles is equal to the…

Q: What volume in of 0.0100 M MnO4 reacts with 0.00200 moles Fe²+ Reaction:- 2+ MnO4 +5√₂²+ +8H+ +…

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Q: A solution of ethanol (d = 0.795 g/mL) and water (H,O) is prepared by placing 30.0 mL of ethanol in…

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Q: Calculate the mass of CO2formed if 150 mL of 0.5 M C4H10reacts with excess O2

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Q: Solution X containing 0.020 mol of iron(II) sulfate requires 22.5 mL of potassium manganate(VII) for…

A: Given: The number of moles (n) is 0.020 mol. The volume of KMnO4 (V) is 22.5 mL.  To find: Molarity…

Q: A solution is made by diluting 254 mL of a 2.27 M KCI stock solution with water to a final volume of…

A: Given, Stock solution of KCl Concentration of the solution (M1) = 2.27 M Volume of the solution (V1)…

Q: M Gmad O CON U Hoe Myl Mal Colon, Ale Join e &lome | Writrg Cen.. O MiGr C What is the molarity of a…

A:

Q: Q1- Calculate the percentage of SnO2 (FW = 150.7 g/mol) in a 1.2362 g sample containing Sn, if the…

A: The given reaction is: Cr2O72-+3Sn2++14H+→2Cr3++3Sn4++7H2O Volume of Cr2O72-=23.15 mL molarity of…