Question

Asked Jan 29, 2019

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59% of all the towns residents own a dog and 69% own a cat. Of the dog owners 43% also own a cat. If a town resident is chosen at a random (round to 4 decimal places where possible)

A . (Own a dog) =

B . (Own a cat) =

C. (Own a cat and a dog )=

D (Own a dog GIVEN own a car)

Step 1

Given 59% of all the towns residents own a dog and 69% own a cat. Of the dog owners 43% also own a cat.

*Known Fact:*

Step 2

*(a) *To find the probability that a randomly selected town resident owns a dog.

Let D be the event that a randomly selected town recident owns a dog.

Let C be the event that a randomly selected town recident owns a cat.

Probability that a randomly selected town recident owns a dog, *P(D)* = 59% = 0.59.

Step 3

*(b) *To find the probability that a randomly selected town recident owns a cat.

Let D be the event that a randomly selected town recident owns a dog.

Let C be the event that a randomly selected town recident owns a cat.

Probability that a randomly selected town recident owns a cat, *P(C)* = 69% = 0.69.

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