64201 2 3 4 5 6 78(s)-2-4-6aP 2.19Runner A is initially 4.0 mi west of a flagpole and is running with a constant velocity of 6.0 mi/ h dueeast. Runner B is initially 3.0 mi east of the flagpole and is running with a constant velocity of 5.0 mi/ hdue west. How far are the runners from the flagpole when they meet?P 2.22The average person passes out at an acceleration of 7g (that is, seven times the gravitational acceleration Earth). Suppose a car is designed to accelerate at this rate. How much time would be required for tcar to accelerate from rest to 60.0 miles per hour? (The car would need rocket boosters!)P 2.23

Question
Asked Sep 5, 2019

I need help on P2.19.

6
4
2
0
1 2 3 4 5 6 78
(s)
-2
-4
-6
a
P 2.19
Runner A is initially 4.0 mi west of a flagpole and is running with a constant velocity of 6.0 mi/ h due
east. Runner B is initially 3.0 mi east of the flagpole and is running with a constant velocity of 5.0 mi/ h
due west. How far are the runners from the flagpole when they meet?
P 2.22
The average person passes out at an acceleration of 7g (that is, seven times the gravitational accelerati
on Earth). Suppose a car is designed to accelerate at this rate. How much time would be required for t
car to accelerate from rest to 60.0 miles per hour? (The car would need rocket boosters!)
P 2.23
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6 4 2 0 1 2 3 4 5 6 78 (s) -2 -4 -6 a P 2.19 Runner A is initially 4.0 mi west of a flagpole and is running with a constant velocity of 6.0 mi/ h due east. Runner B is initially 3.0 mi east of the flagpole and is running with a constant velocity of 5.0 mi/ h due west. How far are the runners from the flagpole when they meet? P 2.22 The average person passes out at an acceleration of 7g (that is, seven times the gravitational accelerati on Earth). Suppose a car is designed to accelerate at this rate. How much time would be required for t car to accelerate from rest to 60.0 miles per hour? (The car would need rocket boosters!) P 2.23

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check_circleExpert Solution
Step 1

The required time is,

5t+6t (4+3)
7
t=hr
11
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5t+6t (4+3) 7 t=hr 11

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Step 2

Therefore, the required tra...

d 6
-3.82 mi
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d 6 -3.82 mi

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