6. A 50-kVA, 2400/240-volt, 60HZ single - phase transformer is supplied with power directly from a large constant-voltage bus. In the short-circuit test, the recorded values on the high-voltage side (with low-voltage winding shorted) are: Vsc = 52 V Isc = 20.8 A Psc = 650 W Find Reg and Xeq referred to the low voltage side of the transformer.
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- A single-phase l0-kVA,2300/230-volt,60-Hz two-winding distribution transformer is connected as an autotransformer to step up the voltage from 2300 to 2530 volts (a) Draw a schematic diagram of this arrangement, showing all voltages and currents when delivering full load at rated voltage. (b) Find the permissible kVA rating of the autotransformer if the winding currents and voltages are not to exceed the rated values as a two-winding transformer. How much of this kVA rating is transformed by magnetic induction? (C) The following data are obtained from tests carried out on the transformer when it is connected as a two-winding transformer: Open-circuit test with the low-voltage terminals excited: Applied voltage =230V, input current =0.45A, input power =70W. Short-circuit test with the high-voltage terminals excited: Applied voltage =120, input current =4.5A, input power =240W. Based on the data, compute the efficiency of the autotransformer corresponding to full load, rated voltage, and 0.8 power factor lagging. Comment on why the efficiency is higher as an autotransformer than as a two-winding transformer.Three single-phase two-winding transformers, each rated 3kVA,220/110volts,60Hz, with a 0.10 per-unit leakage reactance, are connected as a three-phase extended autotransformer bank, as shown in Figure 3.36(c). The low-voltage winding has a 110 volt rating. (a) Draw the positive-sequence phasor diagram and show that the high-voltage winding has a 479.5 volt rating. (b) A three-phase load connected to the low-voltage terminals absorbs 6 kW at 110 volts and at 0.8 power factor lagging. Draw the per-unit impedance diagram and calculate the voltage and current at the high-voltage terminals. Assume positive-sequence operation.A three-phase transformer is rated 1000MVA,220Y/22kV. The Y-equivalent short-circuit impedance, considered equal to the leakage reactance, measured on the low-voltage side is 0.1. Compute the per-unit reactance of the transformer. In a system in which the base on the high-voltage side of the transformer is 100MVA,230kV what value of the per-unit reactance should be used to represent this transformer?
- Given:A single-phase two-winding transformer is rated 20 kVA, 480/120 volts, and 60 Hz. The equivalent leakage impedance of the transformer referred to the 120-volt winding,denoted winding 2, is ???2 = 0.0525∠78.13°?.Find:Using the transformer ratings as base values, determine the per-unit leakage impedance referred to winding 2 referred to winding 1.A three phase Y/A transformer rated at 50 MVA, 230/34.5 kV is to be protected using biased differential circulating current protection scheme. The CT ratio at the high voltage and low voltage side are 250/5 and 900/5 respectively. Draw the protection scheme and determine the current at both side of the transformer.A single-phase 100-kVA, 2400/240-volt, 60-Hz distribution transformer is used as astep-down transformer. The load, which is connected to the 240-volt secondary winding, absorbs 80 kVA at 0.8 power factor lagging and is at 230 volts. Assuming anideal transformer, calculate the following: (a) primary voltage, (b) load impedance,(c) load impedance referred to the primary, and (d) the real and reactive power supplied to the primary winding.
- what are the advantages and disadvantages of single phase dry-type power transformer when used with CNC machine, interms safety concern? please used the clearly suitable clearly labelled diagramsA 25-kVA, 4000/400-V, 60-Hz transformerhas the following parameters: RH =18 Ω, XH = 25 Ω, RL = 180 mΩ, XL = 250m Ω, RCH =15 kΩ, and XMH = 25 kΩ. If the open-circuit and short-circuit tests areperformed on this transformer, what are thereadings of the instruments in each case?calculate: The core-loss resistance,the magnetizing reactance,the rated primary current,the rated secondary current,the percentage of rated load at which the short-circuit test was carried out,the equivalent winding resistance,the total power loss at full load,the per unit efficiency of the transformer when supplying full load at a power factor of 0.8 lagging.
- The label values of the single-phase transformer whose electrical equivalent circuit is given below are 20 kVA, 15400V / 240V, 50 Hz. This transformer Calculate what is required below. a. What is the value of the active power measured in the short circuit test? b. What is the value of the active power measured in the idle test? c. Voltage regulation was found to be 0.1% at 0.8 back power factor. Accordingly, using any method you want Find out how many kVA the transformer draws from the network (primary apparent power).A single-phase 50-kVA, 2400/240-volt, 60-Hz distribution transformer is used as a step-downtransformer at the load end of a 2400-volt feeder whose series impedance is 1.0 + j2.0 ohms.The equivalent series impedance of the transformer is 1.0 + j 2.5 ohms referred to the high- voltage (primary) side. The transformer is delivering rated load at 0.8 power factor lagging and at rated secondary voltage. Neglecting the transformer exciting current, determine a. the voltage at the transformer primary terminals,b. the voltage at the sending end of the feeder, andc. the real and reactive power delivered to the sending end of the feederA 300-kVA, 460-V, balanced three-phase load is supplied by three single phase transformers connected in Δ/Y to form a three-phase transformer. The primary winding of the three-phase transformer is connected to a 4.8 kV, three-phase transmission line. Determine (a) the rated primary voltage and current, (b) the rated secondary voltage and current, and (c) the power rating of each transformer. -What are the primary and secondary line currents?