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6. Evaluate the integral. 5T/2 1 cos 2t dt 2 0 5π/2 1 + cos 2t dt = (Type an exact answer, using t as needed.) 2 0
Given integral is
5я/2 5я2 1 cos 2t (1+ cos 2t )dt 2
We know that integral of cos...
5/2 sin 2t 5я/2 sin5 1 [ 5л sin 0 -0 1cos 2t 1 dt 2 22 2 2 2 2 lo 0 5л/2 1cos 2t -dt 2 57T 4
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