6.0 0 3.0 Ω 6.0 Ω 3.0 0 4.0 0 2.0 N 12 N 18 V Figure P18.15

College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter20: Electric Current, Resistance, And Ohm's Law
Section: Chapter Questions
Problem 48PE: Verify the energy unit equivalence that 1 kWh = 3.60106 J.
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Find the current in the 12 - Ω resistor in Figure P18.15.

6.0 0
3.0 Ω
6.0 Ω
3.0 0
4.0 0
2.0 N
12 N
18 V
Figure P18.15
Transcribed Image Text:6.0 0 3.0 Ω 6.0 Ω 3.0 0 4.0 0 2.0 N 12 N 18 V Figure P18.15
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