6.13 Two samples of RSA ciphertext are presented in Tables 6.2 and 6.3. Yourtask is to decrypt them. The public parameters of the system are n = 18923and b = 1261 (for Table 6.2) and n = 31313 and b = 4913 (for Table 6.3).This can be accomplished as follows. First, factor n (which is easy becauseit is so small). Then compute the exponent a from po(n), and, finally, decryptthe ciphertext. Use the SQUARE-AND-MULTIPLY ALGORITHM to exponentiatemodulo n.In order to translate the plaintext back into ordinary English text, you needto know how alphabetic characters are "encoded" as elements in Zn. Eachelement of Zn represents three alphabetic characters as in the following ex-amples:DOG3 x 26² +14 × 26+6 =CAT → 2x 26² +0 x 26 +19ZZZ=25 x 26² +25 x 26+25=You will have to invert this process as the final step in your program.2398137117575. In 6-13, decrypt the first 5 blocks:n =12423-11524-7243-7459-1430318923, e = 1261

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Answered: 6.13 Two samples of RSA ciphertext are…

Mathematics For Machine Technology

8th Edition

ISBN:9781337798310

Author:Peterson, John.

Publisher:Peterson, John.

Chapter87: An Introduction To G- And M-codes For Cnc Programming

Section: Chapter Questions

Problem 10A

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