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6.4.1 EXERCISES In Exercises 1 - 24, solve the equation analytically. 2. log2 (r*) = log2(r) 1. log(3r – 1) = log(4 – r) %3D 3. In (8 – a?) = In(2 – 2) 4. log, (18 – 2?) = log; (6 – r) 6. log (2r – 1) = -3 5. log3(7 – 2r) = 2 8. log(r2 – 3r) = 1 7. In (22 – 99) = 0 %3D 3x – 2 -(")> 12. 10 log (0-12) 10. log (10-3) 9. log125 = 4.7 %3D 2r + 3 11. – log(r) = 5.4 = 150 14. 3 In(x) – 2 =1- ln(xr) 13. 6 – 3 log; (2x) = 0 15. log3(r – 4) + log3(r+ 4) = 2 16. log, (2r + 1) + log, (r+ 2) 18. In(r+ 1) – ln(r) = 3 17. log 169 (3r + 7)- log169(5x-9) %3! %3D 19. 2log,(r) = log,(2) + log,(r+ 12) 20. log(r) – log(2) = log(r + 8) – log(r + 2) %3D 21. log3(x) = log1 (x) + 8 22. In(In(x)) = 3 %3D 23. (log(r))? = 2 log(r) + 15 24. In(22) = (In(r))² %3D

6.4.1 EXERCISES In Exercises 1 - 24, solve the equation analytically. 2. log2 (r*) = log2(r) 1. log(3r – 1) = log(4 – r) %3D 3. In (8 – a?) = In(2 – 2) 4. log, (18 – 2?) = log; (6 – r) 6. log (2r – 1) = -3 5. log3(7 – 2r) = 2 8. log(r2 – 3r) = 1 7. In (22 – 99) = 0 %3D 3x – 2 -(")> 12. 10 log (0-12) 10. log (10-3) 9. log125 = 4.7 %3D 2r + 3 11. – log(r) = 5.4 = 150 14. 3 In(x) – 2 =1- ln(xr) 13. 6 – 3 log; (2x) = 0 15. log3(r – 4) + log3(r+ 4) = 2 16. log, (2r + 1) + log, (r+ 2) 18. In(r+ 1) – ln(r) = 3 17. log 169 (3r + 7)- log169(5x-9) %3! %3D 19. 2log,(r) = log,(2) + log,(r+ 12) 20. log(r) – log(2) = log(r + 8) – log(r + 2) %3D 21. log3(x) = log1 (x) + 8 22. In(In(x)) = 3 %3D 23. (log(r))? = 2 log(r) + 15 24. In(22) = (In(r))² %3D

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 18E
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6.4.1 EXERCISES In Exercises 1 - 24, solve the equation analytically. 2. log2 (r*) = log2(r) 1. log(3r – 1) = log(4 – r) %3D 3. In (8 – a?) = In(2 – 2) 4. log, (18 – 2?) = log; (6 – r) 6. log (2r – 1) = -3 5. log3(7 – 2r) = 2 8. log(r2 – 3r) = 1 7. In (22 – 99) = 0 %3D 3x – 2 -(")> 12. 10 log (0-12) 10. log (10-3) 9. log125 = 4.7 %3D 2r + 3 11. – log(r) = 5.4 = 150 14. 3 In(x) – 2 =1- ln(xr) 13. 6 – 3 log; (2x) = 0 15. log3(r – 4) + log3(r+ 4) = 2 16. log, (2r + 1) + log, (r+ 2) 18. In(r+ 1) – ln(r) = 3 17. log 169 (3r + 7)- log169(5x-9) %3! %3D 19. 2log,(r) = log,(2) + log,(r+ 12) 20. log(r) – log(2) = log(r + 8) – log(r + 2) %3D 21. log3(x) = log1 (x) + 8 22. In(In(x)) = 3 %3D 23. (log(r))? = 2 log(r) + 15 24. In(22) = (In(r))² %3D
Transcribed Image Text:6.4.1 EXERCISES In Exercises 1 - 24, solve the equation analytically. 2. log2 (r*) = log2(r) 1. log(3r – 1) = log(4 – r) %3D 3. In (8 – a?) = In(2 – 2) 4. log, (18 – 2?) = log; (6 – r) 6. log (2r – 1) = -3 5. log3(7 – 2r) = 2 8. log(r2 – 3r) = 1 7. In (22 – 99) = 0 %3D 3x – 2 -(")> 12. 10 log (0-12) 10. log (10-3) 9. log125 = 4.7 %3D 2r + 3 11. – log(r) = 5.4 = 150 14. 3 In(x) – 2 =1- ln(xr) 13. 6 – 3 log; (2x) = 0 15. log3(r – 4) + log3(r+ 4) = 2 16. log, (2r + 1) + log, (r+ 2) 18. In(r+ 1) – ln(r) = 3 17. log 169 (3r + 7)- log169(5x-9) %3! %3D 19. 2log,(r) = log,(2) + log,(r+ 12) 20. log(r) – log(2) = log(r + 8) – log(r + 2) %3D 21. log3(x) = log1 (x) + 8 22. In(In(x)) = 3 %3D 23. (log(r))? = 2 log(r) + 15 24. In(22) = (In(r))² %3D
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