7) A study of peach trees found that the average number of peaches per tree was 1025. The standard deviation of the population is 35 peaches per tree. A scientist wishes to find the 99% confidence interval for the mean number of peaches per she need to sample to obtain an average accurate to within 18 peaches per tree? tree. How many trees does A) 26 B) 21 ) 23 D) 4

Q: 3, Interpret the statement, "I am 95% confident that the Determine the value of z, that would be…

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A:

Q: If n=550 and ˆpp^ (p-hat) =0.25, find the margin of error at a 99% confidence level Give your…

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A: Given For 99.8% CI is 2.8782 P=0.5 Margin of error=0.06

Q: If n=280 and ˆpp^ (p-hat) =0.83, find the margin of error at a 99% confidence level Give your…

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A: Given, Margin of error=0.09 Confidence level=98% p^=0.15

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A:

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A: Introduction: The 100 (1 – α) % confidence interval for the population proportion, p is: Here, n is…

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A: Given x¯=67.5s=8.3n=7

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A:

Q: If n=160 and ˆp (p-hat) =0.48, find the margin of error at a 99% confidence level

A: Given Data: p^=0.48n=160   We know that, p^-pp^(1-p^)n~ Normal(0,1)

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Q: If n = 560 and ˆpp^ (p-hat) = 0.25, construct a 99% confidence interval.

A: Calculations: x=140 and N= 560

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A: Given, n = 140 p^ = 0.15

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A:

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A: Given : Margin of error (E) = 1% = 0.01 Confidence level = 85% So , significance level (α) = 15% =…

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A:

Q: If n=570 and ˆpp^ (p-hat) =0.8, find the margin of error at a 95% confidence level

A: given that, n = 570 p^=0.8 confidence level = 95%

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A: HERE use basic of confidence interval '

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Q: 9. Find the minimum sample size needed to be within a margin of error of 2% of the population…

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Q: A student was asked to find a 90% confidence interval for widget width using data from a random…

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Q: If n=190 and ˆpp^ (p-hat) =0.17, find the margin of error at a 99% confidence level Give your…

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Q: 7. use the given confidence interval to find the margin of error and the sample proportion.  a.…

A: The objective is to find the margin of error and the sample proportion for the given confidence…