7) It is the value of a2 for a solution with pH =4.40 containing 0.150 M malonic acid (ноосCH-соон, кa1-141х 10°, ка2-2.00 х 104): a.0.0350 b. 0.0466 c. 0.0262 d. 0.0670 e. 0.927

Principles of Modern Chemistry
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Chapter15: Acid–base Equilibria
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7) It is the value of a2 for a solution with pH =4.40 containing 0.150 M malonic acid
(нооссH:Cоон, ка1-141 х 10°, Ка2-2.00х 109):
a.0.0350
b. 0.0466
c. 0.0262
d. 0.0670
e. 0.927
9) Calculate the pH for a solution of N22HPO4 1.00 x 10^-3 M.
Ka2 = 6.32 x 10° and Ka3 = 4.5 x 1013
a.4.40
b. 9.09
c. 12.35
d. 7.20
e. 8.10
10) Calculate grams of K:C:ORa (PM = 166.22; Ka1 = 0.056; Ka2 = 5.42 x 10*) which are
required in such a way that when mixed with 20.0 mL of HCIO4 0.80 M and dilute up to 500.00
ml, result in a shock absorber with pH of 3.30.
а.2.9
ь.6.3
c.5.8
d.12.6
е. 1.45
Transcribed Image Text:I need the answer for this question 7) It is the value of a2 for a solution with pH =4.40 containing 0.150 M malonic acid (нооссH:Cоон, ка1-141 х 10°, Ка2-2.00х 109): a.0.0350 b. 0.0466 c. 0.0262 d. 0.0670 e. 0.927 9) Calculate the pH for a solution of N22HPO4 1.00 x 10^-3 M. Ka2 = 6.32 x 10° and Ka3 = 4.5 x 1013 a.4.40 b. 9.09 c. 12.35 d. 7.20 e. 8.10 10) Calculate grams of K:C:ORa (PM = 166.22; Ka1 = 0.056; Ka2 = 5.42 x 10*) which are required in such a way that when mixed with 20.0 mL of HCIO4 0.80 M and dilute up to 500.00 ml, result in a shock absorber with pH of 3.30. а.2.9 ь.6.3 c.5.8 d.12.6 е. 1.45
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