7 Show how to use the Intermediate Value Theorem to show that the equation 4 has a solution 1+z between 1 and 4. In order for the Internmediate Value Theorem to apply we must first check that f is Select an answer v on the interval [1,4]. You should verify this and be able to explain why it is the case. Let f(2) We check the value of f at the left endpoint of the interval [1,4]: And we check the value of f at the right endpolnt of the Interval [1,4]: The Intermediate Value Theorem guarantees a solution to f(z) 3 in the interval (1,4) because 2.67 1.33

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
Problem 98E: Determine if the statemment is true or false. If the statement is false, then correct it and make it...
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Question
7
Show how to use the Intermediate Value Theorem to show that the equation
has a solution
1+ z?
between 1 and 4.
Let f(x)-
In order for the Intermediate Value Theorem to apply we must first check that f is
Select an answer
|on the interval [1,4]. You should verify this and be able to explain why it is the case.
We check the value of f at the left endpoint of the interval [1,4):
And we check the value of f at the right endpoint of the interval [1,4):
The Intermediate Value Theorem guarantees a solution to f(x) :
in the interval (1,4) because
%3D
2.67-
1.33
Transcribed Image Text:7 Show how to use the Intermediate Value Theorem to show that the equation has a solution 1+ z? between 1 and 4. Let f(x)- In order for the Intermediate Value Theorem to apply we must first check that f is Select an answer |on the interval [1,4]. You should verify this and be able to explain why it is the case. We check the value of f at the left endpoint of the interval [1,4): And we check the value of f at the right endpoint of the interval [1,4): The Intermediate Value Theorem guarantees a solution to f(x) : in the interval (1,4) because %3D 2.67- 1.33
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