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Asked Sep 11, 2019
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7. Calculate the mass of KI in grams required to prepare 5.00 × 102 mL of a 2.80 M solution.

 

 

 

 

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Given Information Volume of solution is 6.00X102 mL Of solution ts 2:80 M Molavity

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Step 2
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The molar mass KI is 166:00 |mol of the solution is Molavity mentioned belon! ren by the lomula as M Number of moles Volume of solution (m L

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he abore formula can le wrillen as shonm below Mass Molar Mass Volume elaviny looo ML actutiona) IL Mass X lo0o mL Molar Macs Volume a solution () 1 L

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Physical Chemistry

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