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Asked Dec 9, 2019
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7. Let P be the plane given by r+y+s=3. Let q= (4,2,3). Find the point on P that is closest to
q.
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7. Let P be the plane given by r+y+s=3. Let q= (4,2,3). Find the point on P that is closest to q.

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Expert Answer

Step 1

Step 2

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х-4 _у-2 1— 3 — х-4%3Dу-2 %3D2-3 Let x- 4= y- 2 = z- 3= k Then x =k +4, y= k + 2,z = k +3

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Step 3

Substitute the values of x, y, z in the plane to find the p...

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k +4+k+2+k +3=3 3k +9=3 3k = 3 – 9 3k = -6 k = -2

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