Question
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Three charged particles are located at the corners of an equilateral triangle as shown in the figure below (let q = 3.40 µC, and L = 0.890 m). Calculate the total electric force on the 7.00-µC charge.

Magnitude in Newtons?

Direction counterclockwise from the x-axis?

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Step 1

Consider the charges on the corners of the equilateral triangle as q, q1, and q2, the distance between the two charged particles as L, the electric force between the particles of charges q and q1 as F1 the electric force between the particles of charges q1 and q2 as F2.

The given values for the equilateral triangle are, help_outlineImage Transcriptioncloseq 3.40 uC = 3.40 x 10 C 7.00 C = 7.00 x 106 C q24.00 uC =-4.00 x 10 C L 0.890 m fullscreen
Step 2

Apply Coulomb’s law to calculate the electric force between the particles of charges q and q1. help_outlineImage Transcriptionclose1 qq 4ле, L (9x10 N m'/C3.40x10 C)(7.00 x 10 C (0.890 m) (3.40x106 C)(7.00 x 10 C) =0.270 N fullscreen
Step 3

Apply Coulomb’s law to calculate the electric force between the part... help_outlineImage Transcriptionclose1 2 = 4πε, 1 0 7.00 x 10 N m2/C2) C4.00 x 10 C) =(9x10 (0.890 m) --0.318 N fullscreen

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