Question
Asked Sep 23, 2019
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7.83 The homogeneous bar AB of weight W and length L is lifted by the
force P that is perpendicular to the bar. Determine the smallest coefficient of
static friction at A that would enable the bar to reach the position B 30°
В
L
A
Fig. P7.83
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7.83 The homogeneous bar AB of weight W and length L is lifted by the force P that is perpendicular to the bar. Determine the smallest coefficient of static friction at A that would enable the bar to reach the position B 30° В L A Fig. P7.83

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Expert Answer

Step 1

The resultant force due to the weight of the homogeneous bar AB acts at a distance of L/2 from A and B.

Show the free body diagram of the homogeneous bar AB as in Figure (1).

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B W L/2 L/2 B=300 F =4,N N Figure

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Step 2

Consider counter clockwise moment is positive and clockwise moment is negative.

Take moment about point A:

Determine the force P using the Equation of equilibrium;

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ΣΜ,-0 PL Wcos B0 P Wcos30° P 0.433W

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Step 3

Consider upward force is positive.

Determine the normal force using the Equation of...

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PcosB- WN = 0 0.433W (cos 30)-W+N = 0 N 0.625W

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