79. Pipe for a water line must be installed from a main water line at point A to a building on Hontoon Island State Park at point install pipe under water is $20 per foot. B as shown in the figure. The cost to install water pipe over land is $10 per foot and the cost to 800 200 f a. Write an expression in terms of 0 to represent the total cost c (in dollars) to lay pipe from point A to point B. b. Use the TABLE function on a calculator to find the cost for e = 20°, 25°, 30°, 35°, and 40°. Round to 1 decimal place. c. Which angle from part (b) yields the least cost? d. Using calculus, we can show that the angle needed to minimize the total cost is a solution to the equation 4000sece tane - 2000 sece = 0. Solve the equation for 0, where 0° < 0 < 90°.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter8: Polynomials
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79. Pipe for a water line must be installed from a main water line at point A to a building on Hontoon Island State Park at point
install pipe under water is $20 per foot.
B as shown in the figure. The cost to install water pipe over land is $10 per foot and the cost to
800
200 f
a. Write an expression in terms of 0 to represent the total cost c (in dollars) to lay pipe from point A to point B.
b. Use the TABLE function on a calculator to find the cost for e = 20°, 25°, 30°, 35°, and 40°. Round to 1 decimal place.
c. Which angle from part (b) yields the least cost?
d. Using calculus, we can show that the angle needed to minimize the total cost is a solution to the equation 4000sece tane - 2000 sece = 0. Solve the equation for 0, where 0° < 0 < 90°.
Transcribed Image Text:79. Pipe for a water line must be installed from a main water line at point A to a building on Hontoon Island State Park at point install pipe under water is $20 per foot. B as shown in the figure. The cost to install water pipe over land is $10 per foot and the cost to 800 200 f a. Write an expression in terms of 0 to represent the total cost c (in dollars) to lay pipe from point A to point B. b. Use the TABLE function on a calculator to find the cost for e = 20°, 25°, 30°, 35°, and 40°. Round to 1 decimal place. c. Which angle from part (b) yields the least cost? d. Using calculus, we can show that the angle needed to minimize the total cost is a solution to the equation 4000sece tane - 2000 sece = 0. Solve the equation for 0, where 0° < 0 < 90°.
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