Question

Asked Oct 30, 2019

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Step 1

a)

The hypotheses for the test are stated below:

From the information, the level of significance is 0.10 and the claim of the test is the mean number of defects per screen may be significantly smaller than 2.58.

The claim of the test is there has been no change in the mean length.

Null hypothesis:

H_{0}: µ = 2.58

Alternative hypothesis:

H_{a}: µ < 2.58

The correct answer is **H _{0}: µ = 2.58 versus H_{a}: µ < 2.58.**

b)

The test statistics is obtained below:

Instructions to obtain the *p*-value for *t* test are listed:

- In EXCEL, Select Add-Ins > PHStat > One-Sample Tests > t Test for the mean, Sigma unknown.
- Enter 58 under Null hypothesis.
- Enter 10 under Level of significance.
- In Sample Statistic Options, choose Sample Statistic unknown $A1$A51.
- In Test Options, choose Two (or Upper or Lower) Tail Test.
- In Output Options, enter a Title and click OK.

Follow the above instructions to obtain the below output:

Step 2

From MegaStat output, the test statistics is −3.3375.

Therefore, the test statistics is **−3.3375.**

c)

From MegaStat output, the ...

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