7q1r2 defects 2 5 0 1 3 1 3 1 1 1 1 5 0 1 4 1 5 1 4 1 3 1 2 2 2 1 3 1 2 1 0 2 3 1 0 0 2 1 1 1 1 0 6 3 0 A quality control engineer at a particular Icd screen manufacturer is studying the mean number of defects per screen. Based on historical evidence, the mean number of defects per screen was thought to be 2.58. There have recently been changes to the manufacturing process, and the engineer now feels that the mean number of defects per screen may be significantly smaller than 2.58. Using the number of defects on each of 50 sample screens shown below, conduct the appropriate hypothesis test using a 0.1 level of significance. Assignment 7q1 data a) What are the appropriate null and alternative hypotheses? 2.58 versus Ha: u < 2.58 Ho: Но: х = 2.58 versus Ha: x > 2.58 Но: и = 2.58 versus Ha: u # 2.58 Но: и %3D 2.58 versus Ha: И> 2.58 b) What is the test statistic? Give your answer to four decimal places. c) What is the P-value for the test? Give your answer to four decimal places. d) What is the appropriate conclusion? Reject the claim that the mean number of defects per screen is 2.58 because the P-value is larger than 0.1. Fail to reject the claim that the mean number of defects per screen is 2.58 because the P-value is larger than 0.1. Reject the claim that the mean number of defects per screen is 2.58 because the P-value is smaller than 0.1. Fail to reject the claim that the mean number of defects per screen is 2.58 because the P-value is smaller than 0.1

Question
7q1r2
defects
2
5
0
1
3
1
3
1
1
1
1
5
0
1
4
1
5
1
4
1
3
1
2
2
2
1
3
1
2
1
0
2
3
1
0
0
2
1
1
1
1
0
6
3
0

Image Transcription

7q1r2 defects 2 5 0 1 3 1 3 1 1 1 1 5 0 1 4 1 5 1 4 1 3 1 2 2 2 1 3 1 2 1 0 2 3 1 0 0 2 1 1 1 1 0 6 3 0

A quality control engineer at a particular Icd screen manufacturer is studying the mean number of defects per screen.
Based on historical evidence, the mean number of defects per screen was thought to be 2.58. There have recently been
changes to the manufacturing process, and the engineer now feels that the mean number of defects per screen may be
significantly smaller than 2.58. Using the number of defects on each of 50 sample screens shown below, conduct the
appropriate hypothesis test using a 0.1 level of significance.
Assignment 7q1 data
a) What are the appropriate null and alternative hypotheses?
2.58 versus Ha: u < 2.58
Ho:
Но: х
= 2.58 versus Ha: x > 2.58
Но: и
= 2.58 versus Ha: u # 2.58
Но: и %3D 2.58 versus Ha: И> 2.58
b) What is the test statistic? Give your answer to four decimal places.
c) What is the P-value for the test? Give your answer to four decimal places.
d) What is the appropriate conclusion?
Reject the claim that the mean number of defects per screen is 2.58 because the P-value is larger than 0.1.
Fail to reject the claim that the mean number of defects per screen is 2.58 because the P-value is larger than 0.1.
Reject the claim that the mean number of defects per screen is 2.58 because the P-value is smaller than 0.1.
Fail to reject the claim that the mean number of defects per screen is 2.58 because the P-value is smaller than 0.1

Image Transcription

A quality control engineer at a particular Icd screen manufacturer is studying the mean number of defects per screen. Based on historical evidence, the mean number of defects per screen was thought to be 2.58. There have recently been changes to the manufacturing process, and the engineer now feels that the mean number of defects per screen may be significantly smaller than 2.58. Using the number of defects on each of 50 sample screens shown below, conduct the appropriate hypothesis test using a 0.1 level of significance. Assignment 7q1 data a) What are the appropriate null and alternative hypotheses? 2.58 versus Ha: u < 2.58 Ho: Но: х = 2.58 versus Ha: x > 2.58 Но: и = 2.58 versus Ha: u # 2.58 Но: и %3D 2.58 versus Ha: И> 2.58 b) What is the test statistic? Give your answer to four decimal places. c) What is the P-value for the test? Give your answer to four decimal places. d) What is the appropriate conclusion? Reject the claim that the mean number of defects per screen is 2.58 because the P-value is larger than 0.1. Fail to reject the claim that the mean number of defects per screen is 2.58 because the P-value is larger than 0.1. Reject the claim that the mean number of defects per screen is 2.58 because the P-value is smaller than 0.1. Fail to reject the claim that the mean number of defects per screen is 2.58 because the P-value is smaller than 0.1

Expert Answer

Want to see the step-by-step answer?

See Answer

Check out a sample Q&A here.

Want to see this answer and more?

Experts are waiting 24/7 to provide step-by-step solutions in as fast as 30 minutes!*

See Answer
*Response times vary by subject and question complexity. Median response time is 34 minutes and may be longer for new subjects.

Related Statistics Q&A

Find answers to questions asked by student like you
Show more Q&A

Q: for a normal distribution with a mean of 7 and a stanard deviation of 6, the value 10 has a z value ...

A: It is given that mean and standard deviation are 7 and 6, respectively.

Q: Question Seventy cards are numbered 1 through 70, one number per card. One card is randomly selec...

A: Define the given events A as multiples of 3 and B as multiples of 5.The events A and B are as follow...

Q: Births are approximately uniformly distributed between the 52 weeks of the year. 1 1 sxs53 f(x) = 52

A: Solution:Continuous uniform distribution:A random variable X is said to have the rectangular distrib...

Q: 1) For a two-tailed hypothesis using a z-distribution, find the critical values (z-scores)that will ...

A: (a)Given: alpha = 0.20.For two tailed test, critical Z value can be calculated as:

Q: An automobile manufacturer finds that 1 in every 2000 automobiles produce has a particular manufactu...

A: Binomial distribution:The events that has exactly two possible outcomes (success or failure) follows...

Q: explain please Discrete random variables (rv); definition, distributions, calculation of probabiliti...

A: Hello there! there are more than 3 sub parts in the question. According to our policies cannot answe...

Q: Question Help An investment counselor calls with a hot stock tip. He believes that if the economy re...

A: Expected value:The expected value of a random variable is the sum of the possible values that the ra...

Q: What would the 95% confidence limits for a sample of 120 with a mean of 51 and a standard deviation ...

A: We are given: 

Q: Suppose an individual was studying temperature’s effect on the crime rate. The researcher looked at ...

A: Solution:The sample mean is obtained below:From the given information, number of observations is 6 a...