7x cos х -7x - lim [sin(-2x)sin(5x)sin(7x)] 2x3cos(x) lim 5x2 х>0

Q: (2-4)* Q1: limx-1 sin(x³–1) x-1

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Q: 2 cos(4x) – 4x2 – 2 lim - I→0 sin(2x)- x2 - 2x

A: We have to evaluate the limit limx→0 2 cos(4x) - 4x2 - 2sin(2x) - x2 - 2x

Q: x²-sin²2x 2) lim x-0 x² 4) lim(1+x) cScx x-0

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Q: 9. Lim 6x - Sin 2x メ→0 2x +3sin 4X b. lim x²-1 1/2

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Q: 3x+7 sin2x x+x.cosx 1- lim- x2-2 lim 2x2+x 3 - lim- x→0 2 - 00+X x→0 sinx.cosx 1 lim x-1- 1-x2 x-3…

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Q: 1-cos(x) Find lim x-0 2x

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Q: 1-cos (x-7) lim ثم اختر الاجابة الصحيحة؟ أحسب الغاية التالية xt (x-n)sin (x-7)

A: We will use the limit theorems to evaluate the limit as x tends to π.

Q: (2) 1: limx-1 sin(x3–1) x-1

A: limx→1 (2-1x)2sin(x3-1)x-1=limx→1 (2x-1x)2sin(x3-1)x-1=limx→1 4x2-4x+1x2sin(x3-1)x-1=limx→1…

Q: lim x → ∞ cos(16/x)^(13.32x^2)

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Q: 1-sinx x-1-cos2x 9) lim 10) lim TC X- sinx-cosx TL X- 4

A:

Q: sin(4x) 8. Compute lim x-0 tan(3x)

A: The solution are next step

Q: 1+x V1-x sin-1(x) [3] limx-0

A: To evaluate: lim[x→01+x-1-xsin-1(x)] Solution: lim[x→01+x-1-xsin-1(x)] On simplifying further we…

Q: 2 -x² + 2x – 7 lim sin 2x5 – x3 + 2x

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Q: cos x lim X-0 x2-x+3 lim 1-vx-6 x-7 x-7 X+7

A: We have to find out limit

Q: -lim COS X tanx <-2メ X-8 2 lim 3 x→2 x42x +X-2 A

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Q: lim (cos(9x)) (+) x-0+

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Q: 1-cos 2x lim x→0 x2

A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: 2x -cos(2x)- 2x - (b) lim | x2

A:

Q: 1- cos(x/6) lim II

A: Solve the limit

Q: x sin(x-1) с) lim х+1 2х2-х-1

A: Solution: The objective is to find the limit value of the given function

Q: 1-cos 2x lim x2 sec x-tan x lim X→0 X→- 2 x- 2 x2 +sin 3x lim 2x+tan 2x . х-0

A: We are solving first question for you. If you want solution for any other question than please…

Q: 2 2- limx-1 sin(x3-1) x-1

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Q: lim cos2x-1/sinx x-> 0

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Q: 4) lim (1 + sin 4x)¹/x x→0+

A: Given limx→x+1+sin(4x)1x

Q: Find the limit.

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Q: 1) lim X-2 2x-4n x(1-cosx) 2) lim х-0 tan(tan?x)

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Q: b) lim sin(x² – 4) х* -16 2х - 3 а) lim %3D V3x² +16 x->2 X->-0

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Q: x²+3 1) lim X00 x2+4 1-cos x sin x 2) lim- X-0 sinx 3) lim X-0 ex-1

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Q: (1 – V3x lim tan- 3 + x x-00

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Q: Vx 6. lim x00 In(x1000) 7. lim 3*-2x X0 x2-x 8. lim 35 sin (nx) cos2 (Tx) 9. lim X-5 2n2(x-5)2

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Q: Inx lim X+o x3 lim- x-0 ex - x2 - 1 lim- 0 sin'3x

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Q: cos x-2sinx 1. limx-n 3cosx -2 limx-3 X-3 3x6-x*+2x-3 limy--o 4x5+2x3-5 iv. lim,→-1(x³ limy--1(x³ –…

A: [i]

Q: 1-sinx x²-49 b. lim x→7 x-7 lim C. lim X→00 x²+1 a. X 1-cosx

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Q: 2tan 'x -x (-) 2x – sin 'x 02. lim, -1

A: Given limx→02tan-1x-x2x-sin-1xTo evaluate the limit:

Q: (1) lim,-0 √x+9-3 X (2) lim-0 1–c05x x sinx (3) limx-1 x²+3x-4 x-1

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Q: (7x – 10,* lim x+0 7x lim 2x sin- 9 sin 27x lim x2 21x lim x+00 12 – 3x

A:

Q: (2-4)² limx-1 sin(x3-1) x-1

A: by using limit algebra and L' hospital rule

Q: x2-4 1) lim x-2 x-2 sin 2x 2) lim 1 3) lim(-- x0 x V

A:

Q: 1) lim-sinxr x-0

A: given equation is     limx--&gt;0  (x-sinx) / x³ ** L hospital rule =&gt;    limx--&gt;0  f(x) /…

Q: 2- x - sinx 1. lim x00 x + cosx x*+2x-1 2. lim-0 x3-2x2+x

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Q: (2-4* limx-1 sin(x³–1) X. x-1

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Q: find lim x-> 0, cos (12x)-1 / 3x

A: Given,              limx→0cos 12x - 13x Move the term 1/3 outside of the limit because it is…

Q: x²+1 4.limx→0 x+cosx 1 х3—1 5.limx→1 х-1 9 – x2 maa - 6. lim x→3 V3 + 2x – x² x4-16 7.limx→2 V x³-8

A: according to our guidelines we can answer only three subparts, or question and rest can be…

Q: x3–1 х-14x3-х-3 1) lim sin 2x 2) lim x→0 2x²+x 3) lim 1-v х-1 1-х

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Q: 1. Lim 2×ー2xーメ+1 x-x3- 2x + 2 3. Lim メ→。 |- Cos X X-1 Sin 2x 2. Lim csc ax Csc 2x 4. Lim 7X 2x+5 x-…

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Q: 1-cos (4x) e) lim x0 2-2cos (6x) (x+1)2 + (2x+3)³ 3x2(8x+1) h) lim X00

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Q: cOs x tan x 28) lim x→0 sin 3x 29) lim x→0 2x x3 + 2x2 + x 30) lim x→-1 x4 + x3 + 2x + 2

A: As per our guidelines we need to solve only 3 questions .please repost the remaining subparts as…

Q: 2 sin x-sin 2x lim х-sin x 3 O -3 6 -6 о O O

A: Given- limx→02sinx-sin2xx-sinx To Find- The valuie of the limit.

Q: 5 sin(6x) lim x→0 3x

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Q: V+12-4 3 .lim X-2 tan3x 2. lim X-0 sinax 4). lim X00 x-7x+1 x-2

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Q: х(4+sin 6x) 3. lim X→+0 х+1

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Q: (1- cos.x)? cosx) limx-0 x sin(x2)

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Q: cos 3x – cos 2x - Evaluate limx→0 x2

A: Consider the given function, limx→0cos3x-cos2xx2 applying the limit to the function we get,…

Q: 1 lim(x²-3x+1) 3. lim tan(x²) 7. lim 2²-1-2 x²-4

A: Since you have posted multiple question in this question which are not interlinked so i have solved…

Q: x2 h) lim - x+0 1- cos?2 x tan 7x i) lim X-0 sin 3x sin(x? + 3x + 2) ji) lim x+ 2

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Q: 2х а) lim -1-2x (sin 2x)+² - et b) lim -4x - cos x

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.