8-69 The bolted connection shown in the figure is subjected to a tensile shear load of 90 kN. The bolts are ISO class 5.8 and the material is cold- drawn AISI 1015 steel. Find the factor of safety of the connection for all possible modes of failure. 35 M30×25
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- Figure 8-19 is a cross-section of ASTM A36. A total of N bolts are to be used to resist a separating force of 7258.97N is one bolt. A) Determine kb,km, and C B) Determine the realized load factor for overload, the yielding factor of safety, and the load factor of joint separation.The figure illustrates the connection of a steel cylinder head to a grade 30 cast-iron pressure vessel using N bolts. A confined gasket seal has an effective sealing diameter D. The cylinder stores gas at a maximum pressure pg. For the specifications given in the table for the specific problem assigned, select a suitable bolt length from the preferred sizes in Table A–17, then determine the yielding factor of safety np, the load factor nL, and the joint separation factor n0. See problem number 8-36, and please use the FEA exponential curve-fit for member stiffness.A spring has a load of 50 lb with a spring index of 8. If the induced stress is 90ksi, determine the wire diameter.
- Q) A helical compression spring of a mechanism is subjected to Pas =120 N 19ad cycle. The diameter if the wire is 3 mm, with a spring index of € = 7 P, =4N and .The spring is made of oil-hardened and tempered steel, with”« ~ L0t dm Determine the factor of safety in fatigue loading.The rotating shaft running at n = 900 rpm, shown in the figure below, is machined from AISI 1045 CD steel. It is subjected to a force of F = 10.1 kN. The shaft is experiencing an operating temperature of 35 oC. With the specified loading and for the reliability of 99.9 %, Determine the minimum factor of safety for fatigue based on infinite life*. Determine the maximum safe load (Fmax) that can be applied for a factor of safety of 1.5 and a design life of 5x105 cycles, all other input values remaining the same. Determine the factor of safety against yielding.A 0.5-in.-diameter steel [E= 30,000 ksi] bolt (1) is placed in a copper tube (2). The copper [E= 16,000 ksi] tube has an outside diameter of 1.00 in., a wall thickness of 0.125 in., and a length of L= 8.0 in. Rigid washers, each with a thickness of t= 0.125 in., cap the ends of the copper tube. The bolt has 20 threads per inch. This means that each time the nut is turned one complete revolution, the nut advances 0.05 in. (i.e., 1/20 in.). The nut is hand-tightened on the bolt until the bolt, nut, washers, and tube are just snug, meaning that all slack has been removed from the assembly but no stress has yet been induced. What stresses are produced in the bolt and in the tube if the nut is tightened an additional quarter turn past the snug-tight condition?
- A helical compression spring is to be used for a maximum load of 1.5 kN using the spring index of 8. The maximum permissible shear stress for the spring wire is 400 MPa. Which of the following is the wire diameter of the spring to be used?Calculate the maximum tensile stress developed in a 1/4-20 bolt (Major dia = 0.2500" and Root dia = 0.1959"), 3" long, and a head height of 0.1875", if it is subjected to a load of 426 lbs.a helical compression spring with squared and ground ends is made of shot-peened astm a232 spring wire with presetting(G=79 GPa) . It is used to control a cyclic dynamic load that varies between 562 and 0 N. if a saftey factor of 1.12 is used, determine the allowable shear stress for a design cinsideration of infinite fatigue life
- A hand cranking lever, as shown in Figure 6 below, is used to start a truck engine byapplying a force F = 400 N. The material of the cranking lever has a yield strength = 320 MPa;Ultimate tensile strength = 500 MPa; Young’s modulus = 205 GPa; Modulus of rigidity = 84 GPaand poisson’s ratio = 0.3. Assuming factor of safety to be 4 based on yield strength, design thediameter of the lever at section X-X near the guide bush using: a) Maximum distortion energytheory; and b) Maximum shear stress theory.A screw clamp shown in the figure has a handle with diameter 5 mm made of cold-drawn AISI 1006 steel (table E18 - page 1195). The overall length of the hand is 75 mm. The screw is M 12 coarse (table 8-1) and is 145 mm long, overall. Distance A is 50 mm. The clamp will accommodate parts up to 105 mm high.a) What is the value of screw torque that causes the handle to bend permanently?b) If the collar friction is neglected and if the thread friction is 0.075, what is the screw force value that causes the handle to bend permanently?c) What is the value of clamping force, which will cause the screw to buckle?d) Are there any other stresses or possible failures to be checked?e) If yes, calculate them.A bracket is under a loading condition shown below. It's made from a steel with yield strength (Sy) of 42 ksi and ultimate tensile strength (Sut) of 76 ksi. The diameter is 0.42 in and b = 1.75 in, with the load P fluctuate between 15 lbs (tension) and -5 lbs (compression). Using the modified Goodman or Gerber criterion, determine the fatigue factor of safety based on infinite life. If infinite life is not predicted, estimate the number of cycles to failure. Also check for yielding.