8. The resting potential of a neuron that is submerged in a solution with zero extracellular potassium will because. A) hyperpolarize; the driving force for potassium to enter the cell increasesB) depolarize; the driving force for potassium to exit the cell increasesC) hyperpolarize; the driving force for potassium to exit the cell increasesD) depolarize; the driving force for potassium to exit the cell decreasesE) hyperpolarize; the driving force for potassium to exit the cell decreases

Question
Asked Sep 12, 2019

8. The resting potential of a neuron that is submerged in a solution with zero extracellular potassium will because. 

A) hyperpolarize; the driving force for potassium to enter the cell increases

B) depolarize; the driving force for potassium to exit the cell increases

C) hyperpolarize; the driving force for potassium to exit the cell increases

D) depolarize; the driving force for potassium to exit the cell decreases

E) hyperpolarize; the driving force for potassium to exit the cell decreases

 

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Expert Answer

Step 1

A resting neuron has a voltage across its membrane called the resting membrane potential, or resting potential. The resting potential is determined by concentration gradients of ions across the membrane and by membrane permeability to each type of ion.

Step 2

At rest, there are relatively more sodium ions outside the neuron and more potassium ions inside the neuron. So, when the resting potential of a neuron is submerged in a solution with zero extracellular potassium, potassium will begin to move down its concentration gradient and come out of the cell. When the opening of channels takes place to let positive ions flow out of the cell, it is known as hyperpolarization. Therefore, the resting potential of the neuron will hyperpolarize because the driving force for potassium to exit the cell increases. So, the correct option is (C) hyperpolarize; the driving force for potassium to exit the cell increases.

Step 3

Hyperpolarization leads to the exit of potassium ions from inside the cell. Therefore, the driving force for potassium to enter the cell cannot increase. Instead, the driving force for potassium to exit the cell will increase. So, option (A) hyperpolarize; the driving force for potassium to enter the cell increases is incorrect.

Depolarization refers to the opening of channels to let positive ions flow into the cell. But during the resting potential of the neuron, the number of potassium ions is more inside the cell than outside. Therefore, the driving force for potassium to exit the cell will increase, and potassium (positive) ions will move out of the cell along its concentration gradient. So, option (B) depolarize; the driving force for potassium to exit the cell increases is incorrect.

Depolarization refers to the opening of channels to let positive ions flow into the cell. But during the restin...

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