(9)10H10-10F-10-510-10.510-1010-5-10-5-10F-10--10-10FO f(x) = -2x + 4o f(x) = -2x + 4o f(x) = -2x + 4O f(x) = -2x + 4O f(x) = -2x2 – 7x-2x2 - 7xO f(x)O f(x) = -2x2-2x2- 7xO f(x) =7x5x2-* + 5x2o f(x) = - *o f(x) = -+ 5x23O f(x)+ 5x2o f(x)3O f(x) = x4 + 3x3O f(x) = x4 + 3x³O f(x) = x4 + 3x3O f(x) = x4 + 3x3O f(x) = x2 –O f(x) = x2 - 3x- 3xO f(x) = x2- 3xO f(x) = x2- 3xO f(x) = 2x3 - 3x + 12x3 – 3x + 1O f(x)2x3O f(x)O f(x) = 2x3 - 3x + 1- 3x + 1%3Do Ax) = -o Pa) =+ x? -4+ x? -+ x2 -3o Rx) = -+ x23O f(x)+ x2 -O f(x)= -3- 2r3 + xo fx) =- 2x3 +x9.-хo (x) = 5 - 2x3 +O f(x) =(d)(b)y(f)У(h)yy10-10-10-10х-10-51010-10-5-10-10-5-5-10--10F-10--10-o f(x) = -2x + 4o f(x) = -2x + 4O f(x) = -2x + 4o f(x) = -2x + 4O f(x) = -2x2 – 7xO f(x) = -2x² – 7xO f(x)-2x27xO f(x) = -2x2- 7x1,4 + 5x23글 + 5x2o f(x)o f(x) = -O f(x)+ 5x25x2O f(x) = -O f(x) = x4 + 3x3O f(x) = x4 + 3x3O f(x) = x4 + 3x3O f(x) = x4 + 3x3O f(x) = x2 - 3xO f(x) = x2 - 3xO f(x) = x2- 3x· 3xO f(x) = x22x3 - 3x + 1O f(x) = 2x3 - 3x + 1O f(x)O f(x) = 2x3 - 3x + 1O f(x) = 2x3 - 3x + 1%3Do Rw) = - * -o M) = -Rx) = -+ x2 -4+ x2O (x)4+ x² -O f(x)O f(x)333x5 - 2x3 +.2x39.o f(x)RA) =5 - 2x3 +.O Fx) = 5 - 2x3O (x) =O f(x)-5

Question
Asked Jan 24, 2020
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Match the polynomial function with its graph: [A] through [H]

(9)
10H
10-
10F
-10
-5
10
-10
.5
10
-10
10
-5
-10
-5
-10F
-10-
-10
-10F
O f(x) = -2x + 4
o f(x) = -2x + 4
o f(x) = -2x + 4
O f(x) = -2x + 4
O f(x) = -2x2 – 7x
-2x2 - 7x
O f(x)
O f(x) = -2x2
-2x2
- 7x
O f(x) =
7x
5x2
-* + 5x2
o f(x) = - *
o f(x) = -
+ 5x2
3
O f(x)
+ 5x2
o f(x)
3
O f(x) = x4 + 3x3
O f(x) = x4 + 3x³
O f(x) = x4 + 3x3
O f(x) = x4 + 3x3
O f(x) = x2 –
O f(x) = x2 - 3x
- 3x
O f(x) = x2
- 3x
O f(x) = x2
- 3x
O f(x) = 2x3 - 3x + 1
2x3 – 3x + 1
O f(x)
2x3
O f(x)
O f(x) = 2x3 - 3x + 1
- 3x + 1
%3D
o Ax) = -
o Pa) =
+ x? -
4
+ x? -
+ x2 -
3
o Rx) = -
+ x2
3
O f(x)
+ x2 -
O f(x)
= -
3
- 2r3 + x
o fx) =
- 2x3 +x
9.
-х
o (x) = 5 - 2x3 +
O f(x) =
(d)
(b)
y
(f)
У
(h)
y
y
10-
10-
10-
10
х
-10
-5
10
10
-10
-5
-10
-10
-5
-5
-10-
-10F
-10-
-10-
o f(x) = -2x + 4
o f(x) = -2x + 4
O f(x) = -2x + 4
o f(x) = -2x + 4
O f(x) = -2x2 – 7x
O f(x) = -2x² – 7x
O f(x)
-2x2
7x
O f(x) = -2x2
- 7x
1,4 + 5x2
3
글 + 5x2
o f(x)
o f(x) = -
O f(x)
+ 5x2
5x2
O f(x) = -
O f(x) = x4 + 3x3
O f(x) = x4 + 3x3
O f(x) = x4 + 3x3
O f(x) = x4 + 3x3
O f(x) = x2 - 3x
O f(x) = x2 - 3x
O f(x) = x2
- 3x
· 3x
O f(x) = x2
2x3 - 3x + 1
O f(x) = 2x3 - 3x + 1
O f(x)
O f(x) = 2x3 - 3x + 1
O f(x) = 2x3 - 3x + 1
%3D
o Rw) = - * -
o M) = -
Rx) = -
+ x2 -
4
+ x2
O (x)
4
+ x² -
O f(x)
O f(x)
3
3
3
x5 - 2x3 +.
2x3
9.
o f(x)
RA) =
5 - 2x3 +.
O Fx) = 5 - 2x3
O (x) =
O f(x)
-
5
help_outline

Image Transcriptionclose

(9) 10H 10- 10F -10 -5 10 -10 .5 10 -10 10 -5 -10 -5 -10F -10- -10 -10F O f(x) = -2x + 4 o f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x + 4 O f(x) = -2x2 – 7x -2x2 - 7x O f(x) O f(x) = -2x2 -2x2 - 7x O f(x) = 7x 5x2 -* + 5x2 o f(x) = - * o f(x) = - + 5x2 3 O f(x) + 5x2 o f(x) 3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x³ O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x2 – O f(x) = x2 - 3x - 3x O f(x) = x2 - 3x O f(x) = x2 - 3x O f(x) = 2x3 - 3x + 1 2x3 – 3x + 1 O f(x) 2x3 O f(x) O f(x) = 2x3 - 3x + 1 - 3x + 1 %3D o Ax) = - o Pa) = + x? - 4 + x? - + x2 - 3 o Rx) = - + x2 3 O f(x) + x2 - O f(x) = - 3 - 2r3 + x o fx) = - 2x3 +x 9. -х o (x) = 5 - 2x3 + O f(x) = (d) (b) y (f) У (h) y y 10- 10- 10- 10 х -10 -5 10 10 -10 -5 -10 -10 -5 -5 -10- -10F -10- -10- o f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x2 – 7x O f(x) = -2x² – 7x O f(x) -2x2 7x O f(x) = -2x2 - 7x 1,4 + 5x2 3 글 + 5x2 o f(x) o f(x) = - O f(x) + 5x2 5x2 O f(x) = - O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x2 - 3x O f(x) = x2 - 3x O f(x) = x2 - 3x · 3x O f(x) = x2 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 O f(x) O f(x) = 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 %3D o Rw) = - * - o M) = - Rx) = - + x2 - 4 + x2 O (x) 4 + x² - O f(x) O f(x) 3 3 3 x5 - 2x3 +. 2x3 9. o f(x) RA) = 5 - 2x3 +. O Fx) = 5 - 2x3 O (x) = O f(x) - 5

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Part (a):

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Step 3

The x – intercept of graph at x = -3 and x = 0. From graph, the minimum value of function occu...

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