College Algebra
College Algebra
7th Edition
ISBN: 9781305115545
Author: James Stewart, Lothar Redlin, Saleem Watson
Publisher: Cengage Learning
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Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.
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Match the polynomial function with its graph: [A] through [H]

(9) 10H 10- 10F -10 -5 10 -10 .5 10 -10 10 -5 -10 -5 -10F -10- -10 -10F O f(x) = -2x + 4 o f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x + 4 O f(x) = -2x2 – 7x -2x2 - 7x O f(x) O f(x) = -2x2 -2x2 - 7x O f(x) = 7x 5x2 -* + 5x2 o f(x) = - * o f(x) = - + 5x2 3 O f(x) + 5x2 o f(x) 3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x³ O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x2 – O f(x) = x2 - 3x - 3x O f(x) = x2 - 3x O f(x) = x2 - 3x O f(x) = 2x3 - 3x + 1 2x3 – 3x + 1 O f(x) 2x3 O f(x) O f(x) = 2x3 - 3x + 1 - 3x + 1 %3D o Ax) = - o Pa) = + x? - 4 + x? - + x2 - 3 o Rx) = - + x2 3 O f(x) + x2 - O f(x) = - 3 - 2r3 + x o fx) = - 2x3 +x 9. -х o (x) = 5 - 2x3 + O f(x) = (d) (b) y (f) У (h) y y 10- 10- 10- 10 х -10 -5 10 10 -10 -5 -10 -10 -5 -5 -10- -10F -10- -10- o f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x2 – 7x O f(x) = -2x² – 7x O f(x) -2x2 7x O f(x) = -2x2 - 7x 1,4 + 5x2 3 글 + 5x2 o f(x) o f(x) = - O f(x) + 5x2 5x2 O f(x) = - O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x2 - 3x O f(x) = x2 - 3x O f(x) = x2 - 3x · 3x O f(x) = x2 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 O f(x) O f(x) = 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 %3D o Rw) = - * - o M) = - Rx) = - + x2 - 4 + x2 O (x) 4 + x² - O f(x) O f(x) 3 3 3 x5 - 2x3 +. 2x3 9. o f(x) RA) = 5 - 2x3 +. O Fx) = 5 - 2x3 O (x) = O f(x) - 5
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Transcribed Image Text:(9) 10H 10- 10F -10 -5 10 -10 .5 10 -10 10 -5 -10 -5 -10F -10- -10 -10F O f(x) = -2x + 4 o f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x + 4 O f(x) = -2x2 – 7x -2x2 - 7x O f(x) O f(x) = -2x2 -2x2 - 7x O f(x) = 7x 5x2 -* + 5x2 o f(x) = - * o f(x) = - + 5x2 3 O f(x) + 5x2 o f(x) 3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x³ O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x2 – O f(x) = x2 - 3x - 3x O f(x) = x2 - 3x O f(x) = x2 - 3x O f(x) = 2x3 - 3x + 1 2x3 – 3x + 1 O f(x) 2x3 O f(x) O f(x) = 2x3 - 3x + 1 - 3x + 1 %3D o Ax) = - o Pa) = + x? - 4 + x? - + x2 - 3 o Rx) = - + x2 3 O f(x) + x2 - O f(x) = - 3 - 2r3 + x o fx) = - 2x3 +x 9. -х o (x) = 5 - 2x3 + O f(x) = (d) (b) y (f) У (h) y y 10- 10- 10- 10 х -10 -5 10 10 -10 -5 -10 -10 -5 -5 -10- -10F -10- -10- o f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x + 4 o f(x) = -2x + 4 O f(x) = -2x2 – 7x O f(x) = -2x² – 7x O f(x) -2x2 7x O f(x) = -2x2 - 7x 1,4 + 5x2 3 글 + 5x2 o f(x) o f(x) = - O f(x) + 5x2 5x2 O f(x) = - O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x4 + 3x3 O f(x) = x2 - 3x O f(x) = x2 - 3x O f(x) = x2 - 3x · 3x O f(x) = x2 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 O f(x) O f(x) = 2x3 - 3x + 1 O f(x) = 2x3 - 3x + 1 %3D o Rw) = - * - o M) = - Rx) = - + x2 - 4 + x2 O (x) 4 + x² - O f(x) O f(x) 3 3 3 x5 - 2x3 +. 2x3 9. o f(x) RA) = 5 - 2x3 +. O Fx) = 5 - 2x3 O (x) = O f(x) - 5
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