Can somebody help me on how to evaluate the integral.
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- 9 64 dx x2 - 64 X° -oo
Refer to the question, first evaluate the given integral in indefinite form that is with the limits.
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64 -dx (64sx2 -64dt) x264
Now use partial differentiation to solve the integration.
So the formula of partial fraction decomposition of given integral is,
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1 1 x-64 x8(x +8) Then Partial fraction decomposition, 1 B A (x-8)(x+8) x-8 x+8
Now find the value of A and...
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1 В A (х-8)(х+8) х - 8 x +8 As,denominator are equal, So equate the numerator А(х +8) В(x-8) 1 (x-8)(x+8) х -8 1%3D A(х +8)+ B(х-8) 1 xABx 8A -8B 1 (A B)x8.A -8B
Math
Calculus
Integration
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