9. In human beings, the gene for red-green colorblindness (r) is sex-linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal-visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. a. What is the genotype of the woman's father? b. What is the probability that the couple's first child will be a non-freckled, normal visioned girl c. What is the probability that the first two children born to the couple will be freckled and colorblind girls? d. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non-freckled, normal visioned girl or a non-freckled, normal visioned boy e. What is the probability that the first four children born to the couple will be freckled and normal visioned girls?

9. In human beings, the gene for red-green colorblindness (r) is sex-linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal-visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. a. What is the genotype of the woman's father? b. What is the probability that the couple's first child will be a non-freckled, normal visioned girl c. What is the probability that the first two children born to the couple will be freckled and colorblind girls? d. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non-freckled, normal visioned girl or a non-freckled, normal visioned boy e. What is the probability that the first four children born to the couple will be freckled and normal visioned girls?

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter12: Mendel, Genes, And Inheritance

Section: Chapter Questions

Problem 9TYK: The ability of humans to taste the bitter chemical phenylthiocarbamide (PTC) is a genetic trait....

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In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?
The following pedigree shows the pattern of inheritance of red green color blindness in a family. Females are shown as circles and males as squares; the squares or circles of individuals affected by the trait are filled in red. What is the chance that a son of the third-generation female indicated by the arrow will be color-blind if the father is a normal man? If the father is color-blind?
In peas, the allele Le produces tall plants and the allele le produces dwarf plants. The Le allele is dominant to le. If a tall plant is crossed with a dwarf, the offspring are distributed about equally between tall and dwarf plants. What are the genotypes of the parents?
Several alleles affect traits of roses, such as plant form and bud shape. Alleles of one gene govern whether a plant will be a climber (dominant) or shrubby (recessive). All F1 offspring from a cross between a true-breeding climber and a shrubby plant are climbers. If an F1 plant is crossed with a shrubby plant, about 50 percent of the offspring will be shrubby; 50 percent will be climbers. Using symbols A and a for the dominant and recessive alleles, make a Punnett- square diagram of the expected genotypes and phenotypes the cross between the F1 offspring and the shrubby plant.
A true-breeding rabbit with agouti (mottled, grayish brown) fur crossed with a true-breeding rabbit with chinchilla (silver) fur produces all agouti offspring. A true-breeding chinchilla rabbit crossed with a true-breeding Himalayan rabbit (white fur with pigmented nose, ears, tail, and legs) produces all chinchilla offspring. A true-breeding Himalayan rabbit crossed with a true-breeding albino rabbit produces all Himalayan offspring. Explain the inheritance of the fur colors.
Individuals affected by a condition known as polydactyly have extra fingers or toes. The following pedigree shows the pattern of inheritance of this trait in one family: From the pedigree, can you tell if polydactyly comes from a dominant or recessive allele? Is the trait sex-linked? As far as you can determine, what is the genotype of each person in the pedigree with respect to the trait?
3. A couple just had a baby, who has type-O blood. Upon learning the baby’s blood type, the father becomesinfuriated and accuses the mother of cheating on him. The mother has type-A blood and the father has type-Bblood. Knowing that the allele for type-O is recessive, answer the following questions.a. What is the relationship between the IA, IB, and i alleles?b. Is the father right? Or is he falsely accusing the mother? Explain. Include the genotypes of the parentsand the genotypes of their potential children.
7. The ability to roll your tongue (R) is dominant to lack of this ability (r). A. What is the genotype of a man who can roll his tongue if his father couldn’t? B. If a man who is heterozygous for tongue rolling marries a woman who is heterozygous, what would you predict for the genotypes and phenotypes of their children?
1. In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and eindicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit flyproduced the following offspring.Wild-typeMaleWild-typeFemaleWhite-eyedMaleWhite-eyedFemaleBrown-eyedFemaleF1 0 45 55 0 1The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the followingoffspring.F2 23 31 22 24 0(a) Determine the genotypes of the original parents (P generation) and explain your reasoning. You may usePunnett squares to enhance your description, but the results from the Punnett squares must be discussed inyour answer.(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Showall your work and explain the importance of your final answer.(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is,and discuss…
2.In dogs, there is a hereditary deafness caused by a recessive allele, d. A kennel owner has a male dog that she wants to use for breeding purposes if possible. The dog can hear, but the owner is unsure of the genotype. She does a testcross (crosses it to a homozygous recessive dog), and two of the five offspring are deaf. This means that the male dog A.has the genotype DD B.has the genotype Dd C.is still of unknown genotype since there were offspring of both deaf and hearing phenotypes. D.has the genotype dd
4. Huntington diseases is a rare fatal, degenerative neurological disease in which individuals start to show symptoms in their 40s. It is caused by a dominant allele. Joe, a man in his 20s, just learned that his father has Huntington disease. a. What is the probability that Joe will also develop the disease?b. Joe and his new wife have been eager to start a family. What is the probability that their first child will eventually develop the disease?
1. A sex-linked recessive allele rg causes a red-green colorblindness in humans. A normal woman whose father was colorblind marries a colorblind man. A. Of all the children of these parents (sex unspecified), what proportion can be expected to have normal color vision?