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9t+3 all over 6t-5 = 3t+6 all over 3t-5

Question

9t+3 all over 6t-5 = 3t+6 all over 3t-5

check_circleAnswer
Step 1

Refer to the question,

According to the language of the question the equation formed is as,

(9r 3)_(3+6)
(61-5) (31-5)
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(9r 3)_(3+6) (61-5) (31-5)

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Step 2

Apply fraction cross multiple as,

b d
Then
ad bc
(9t+3)_(3t+6)
(3t +6)
So
(бr - 5) (3г -5)
(9r+3)(3г-5) - (бг - 5)(3г + 6)
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b d Then ad bc (9t+3)_(3t+6) (3t +6) So (бr - 5) (3г -5) (9r+3)(3г-5) - (бг - 5)(3г + 6)

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Step 3

Now expand (9t+3)(3t-5) and sim...

(91+3)(3f -5)27
-36t -15
And
(61-5(3t6) =18t2 +21f -30
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(91+3)(3f -5)27 -36t -15 And (61-5(3t6) =18t2 +21f -30

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Equations and In-equations

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