Question

Asked Oct 7, 2019

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A 0.510-mm-diameter silver wire carries a 30.0 mA current. What is the electric field in the wire?

Step 1

Given values:

Radius of silver wire, r = diameter/2 = 0.51/2 =0.255 mm =0.255 x 10^{-3}m = 2.55 x 10^{-4} m

Current in the wire, I = 30.0 mA = 30 x 10^{-3} A

Resistivity of silver = 1.59 × 10^{−8} Ω m

Step 2

The relation between current density and electric field:

Step 3

Plugging in the...

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