Asked Oct 14, 2019

A 0.760 kg snowball is fired from a cliff 13.4 m high with an initial velocity of 11.7 m/s, directed 29.0° above the horizontal. (a) Using energy techniques, find the speed of the snowball as it reaches the ground below the cliff. What is that speed (b) if the launch angle is changed to 29.0° below the horizontal and (c) if the mass is changed to 1.30 kg?


Expert Answer

Step 1

The conservation of energy states that initial energy of the snowball is equal to the final energy of the snowball.

Step 2

(a) Use the conservation law of energy,


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initial enrgy = final energy 1 1 mghmu 2 2

Step 3

Use equation (1) to...


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v= \u2 +2gh (11.7m/s)+2(9.8m/s2)(13.4m) - 19.99m/s


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