Question
Asked Oct 10, 2019

A 0.8 kg ball is traveling at 4.0 m/s and strikes a wall. The ball bounces off the wall with a velocity of 4.0 m/s in the opposite direction. If the contact with the wall by the ball lasts for 0.13 seconds, then the magnitude of the impulse on the ball is

check_circleExpert Solution
Step 1
According to the impulse-momentum theorem, the magnitude of the impulse on the ball is equal to the
change in momentum of the ball
The equation for the change in momentum of the ball is given by
AP m(v (1)
Here, AP is the change in momentum of the ball, m is the mass of the ball, v is the initial velocity of
the ball and v, is the final velocity of the ball
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According to the impulse-momentum theorem, the magnitude of the impulse on the ball is equal to the change in momentum of the ball The equation for the change in momentum of the ball is given by AP m(v (1) Here, AP is the change in momentum of the ball, m is the mass of the ball, v is the initial velocity of the ball and v, is the final velocity of the ball

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