A 0.867 kg sample of ethanol is in its liquid state at its boiling temperature of 78 C. If 1.93e5 J of energy are transferred into the sample, what percentage of the sample is vaporized? ethanol has: a specific heat of 1000 J/kgK in solid form, a specific heat of 2010 J/kgK in liquid form, a freezing temperature of –114 C a boiling temperature of 78 C, a latent heat of fusion of 1.05e5 J/kg, and a latent heat of vaporization of 8.54e5 J/kg

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Chapter20: The First Law Of Thermodynamics
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A 0.867 kg sample of ethanol is in its liquid state at its boiling temperature of 78 C. If 1.93e5 J of energy are transferred into the sample, what percentage of the sample is vaporized?
ethanol has:
a specific heat of 1000 J/kgK in solid form,
a specific heat of 2010 J/kgK in liquid form,
a freezing temperature of –114 C
a boiling temperature of 78 C,
a latent heat of fusion of 1.05e5 J/kg, and
a latent heat of vaporization of 8.54e5 J/kg
Expert Solution
Step 1

Consider an ethanol of mass m having latent heat of vaporization Lv and Qgiven is the amount of heat is given to the sample.

m 0.867 kg
L-8.54x10 kg
Qgven =1.93x10 J
given
Step 2

Write the formula for heat(Qrequired) required to change its state to vapour from liquid of the entire ethanol and plug the required values to find it.

Qrequired mL
=(0.867 kg)(8.54x10 Jkg)
= 7.4x10 J
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