Question
Asked Feb 22, 2020
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A 100.-mL reaction vessel initially contains 2.60 × 10–2 mol of NO and 1.30 × 10–2 mol of H2. At equilibrium, the concentration of NO in the vessel is 0.161 M. At equilibrium the vessel also contains N2, H2O, and H2.

The balanced equation for the reaction is given below.

 2H2​(g)+2NO(g)<------>2H2​O(g)+N2(g)

Determine the equilibrium concentration of H2O (Water)

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Expert Answer

Step 1

The equilibrium constant, Keq for a reaction is given as :

Chemistry homework question answer, step 1, image 1

Step 2

Given,

Volume of vessel = 100 mL = 0.1 L   (1 mL = 0.001 L)

Initial moles of NO = 2.60 × 10-2 mol

Initial moles of H2 = 1.30 × 10-2 mol

Equilibrium concentration of NO = 0.161 M

 

Initial concentration of NO and H2 can be calculated as :

Chemistry homework question answer, step 2, image 1

Step 3

The balanced reaction is given as :

2 H2 (g) + 2 NO (g) ↔ 2 H2O (g) + N2 (g)       

 

The ICE table for this reaction can be written as:

Chemistry homework question answer, step 3, image 1

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