# A 100.-mL reaction vessel initially contains 2.60 × 10–2 mol of NO and 1.30 × 10–2 mol of H2. At equilibrium, the concentration of NO in the vessel is 0.161 M. At equilibrium the vessel also contains N2, H2O, and H2.The balanced equation for the reaction is given below. 2H2​(g)+2NO(g)<------>2H2​O(g)+N2(g)Determine the equilibrium concentration of H2O (Water)

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A 100.-mL reaction vessel initially contains 2.60 × 10–2 mol of NO and 1.30 × 10–2 mol of H2. At equilibrium, the concentration of NO in the vessel is 0.161 M. At equilibrium the vessel also contains N2, H2O, and H2.

The balanced equation for the reaction is given below.

2H2​(g)+2NO(g)<------>2H2​O(g)+N2(g)

Determine the equilibrium concentration of H2O (Water)

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Step 1

The equilibrium constant, Keq for a reaction is given as : Step 2

Given,

Volume of vessel = 100 mL = 0.1 L   (1 mL = 0.001 L)

Initial moles of NO = 2.60 × 10-2 mol

Initial moles of H2 = 1.30 × 10-2 mol

Equilibrium concentration of NO = 0.161 M

Initial concentration of NO and H2 can be calculated as : Step 3

The balanced reaction is given as :

2 H2 (g) + 2 NO (g) ↔ 2 H2O (g) + N2 (g)

The ICE table for this reaction can be written as: ...

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