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A 155.0 g piece of copper at 146 oC is dropped into 250.0 g of water at 15.3 oC. (The specific heat of copper is 0.385 J/goC.) Calculate the final temperature of the mixture. (Assume no heat loss to the surroundings.)

Question

A 155.0 g piece of copper at 146 oC is dropped into 250.0 g of water at 15.3 oC. (The specific heat of copper is 0.385 J/goC.) Calculate the final temperature of the mixture. (Assume no heat loss to the surroundings.)

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Step 1

The heat lost by copper will be equal to the heat gained by water as there is no loss of heat to the surrounding. The final temperature of the mixture can be calculated as,

Qlost Qgained
Qm C AT
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Qlost Qgained Qm C AT

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Step 2

The heat lost by copper having a mass of 155 g is calculated as,

Qlost mcopper X Ccopper X (Tinitial- Tfinal)
Qlost 155 x 0.385 x (146 - Tfinal)
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Qlost mcopper X Ccopper X (Tinitial- Tfinal) Qlost 155 x 0.385 x (146 - Tfinal)

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Step 3

The heat gained by water having a mass of 250 g and specific hea...

Qgained mwater X Cwater X (Tfinal- Tinitial)
Qgained 250 x 4.186 x (Tfinal- 15.3)
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Qgained mwater X Cwater X (Tfinal- Tinitial) Qgained 250 x 4.186 x (Tfinal- 15.3)

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