Question
Asked Oct 15, 2019
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A 15-gram sample of lead (c = 0.128 J/g degrees celsius) is heated from 25 degrees celsius to 215 degrees celsius. How much heat is absorbed?

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Expert Answer

Step 1

The specific heat capacity for a given substance refers to the amount of heat that is needed to raise the temperature of a given substance per unit of its mass. The relationship between specific heat capacity, mass, change in temperature and the heat of the solution is given by the following equation:

q=mxcxAT
q is the amount of heat released or absorbed during the reaction
m is the mass of the given substance
c is the specific heat capacity
AT is the chnage in the temperature of the system
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q=mxcxAT q is the amount of heat released or absorbed during the reaction m is the mass of the given substance c is the specific heat capacity AT is the chnage in the temperature of the system

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Step 2

In this problem, it has been given that the mass of the sample of lead is 15 g.

The change in temperature is given to be from 25oC to 215oC which can be calculated as follows:

ΔΤ-Τ1
=215°C-25°C
=190°C
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ΔΤ-Τ1 =215°C-25°C =190°C

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Step 3

The specific heat capacity of the sample of lead is given to be 0.128 J/g oC

S...

q=mxcxAT
q=15 g x0.128 J/g °Cx190°C
=364.8 J
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q=mxcxAT q=15 g x0.128 J/g °Cx190°C =364.8 J

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