Answered: A 2 kg ball is moving at 2.4 m/s…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter10: Systems Of Particles And Conservation Of Momentum

Section: Chapter Questions

Problem 27PQ

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A 2 kg ball is moving at 2.4 m/s perpendicular to a wall. Upon hitting the wall, the ball rebounds at 1.0 m/s in the opposite direction. What is the magnitude of the impulse of the ball? (units in kg m/s)

Expert Solution

Step 1

The initial momentum of the ball is.

The final velocity of the ball rebounds in opposite direction so the final momentum is,

P; = mv;
=(2kg)(2.4m/s)
= 4.8kg - m/s
P; = mv;
=(2kg)(-1.0m/s)
=-2.0kg m/s

Step 2

The impulse imparted to the ball is,

Substitute the values, to find the magnitude of the impulse imparted to the ball.

J = Ap
= P;- P,
J=-2.0kg - m/s – 4.8kg m/s
=-6.8kg - m/s
|J|=6.8kg - m/s

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