A 2.0 kg block slides along a frictionless surface at 1.0 m/s. A second block, sliding at 4.0 m/s, collides with the first from behind and sticks to it. The final velocity of the combined blocks is 2.0 m/s. What was the mass of the second block?

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A: It is given that

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A: Given:mass of the car, m = 1000 kgintial velocity of car, u = +26 m/smass of the truck, M = 2000…

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A: DATA   Mass of each bullet,  m=0.014 kg   Firing rate, n=4.8/s   Speed, v=640 m/sREQUIRED    Average…

Q: Two carts collide head-on and then ricochet off each other in opposite directions on a frictionless…

A: Given data:      Mass, m1 = 0.350kg       Mass, m2 = 0.500kg     Initial velocity, u1 = 1.50m/s…

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A:

Q: Hinata throws a 0.3-kg volleyball at the wall. With a velocity of 3.2 m/s, the volleyball hits the…

A: mass of volleyball (m) = 0.3 kg Initial velocity (u) = 3.2  msFinal velocity (v) = - 2.1 ms

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A:

Q: An object of mass 2.91 kg, moving with an initial velocity of 5.02  m/s, collides with and sticks to…

A: Given m1 = 2.91 kg m2 = 1.96 kg v1 = 5.02m/s v2 = -3.83 m/s We have to find out final velocity of…

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Q: An internal explosion breaks an object into two fragments. One fragment is 2.35 kg moving 30° north…

A: Mass of one fragment: m1=2.35 [kg] Velocity of fragment: v1=3.5 [m/s] Mass of other fragment:…

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A: From the conservation of momentum, the expression for the momentum of the system is:

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A: Given data: Mass of first object (m1) = 10 kg Initial velocity of first mass (u1) = 5.4 m/s Mass of…

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A:

Q: A 10.50-g bullet is fired into a stationary block of wood having mass m = 4.980 kg. The bullet…

A: We are going to apply conservation of momentum to solve the problem. Final answer is 289.4 in four…

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A: The final momentum will be, mfv=m1v1+m2v2v2=mfv-m1v1m2

Q: 4. what is the velocity of the 30 g block after the collision? с. 15 ст/s a. 20 cm/s b. 5 ст/s d.…

A: We have to find the velocity of the 30 g block after the Collison.

Q: A 1200-kg car moving at 15.6 m/s suddenly collides with a stationary car of mass 1500 kg. If the two…

A:

Q: A 9.7-g bullet is fired into a stationary block of wood having mass m = 5.10 kg. The bullet imbeds…

A: According to conservation of momentum momentum before collision=momentum after collision Momentum=mV

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A: Given : m1 = 2100 kg u1 = 25 m/s m2 = 1650 kg u2 = 21 m/s

Q: A 0.0065 kg bullet is fired into a stationary concrete piece that weighs 3.0 kg. The bullet imbeds…

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Q: A bowling ball with a mass of 7.0 kg strikes a pin that has a mass of 2.0 kg. The pin flies forward…

A: Given: mb =7.0kg mp =2.0kg v1b =4.0m/s v1p =6.0m/s v0p=0m/s To find: vob.

Q: A 2400 kg truck is traveling at 24 m/s and runs into the back of a 1200 kg Mini Cooper. Immediately…

A: Option (E) is correct. Explanation is given in attached images.

Q: A 10.0-g bullet is fired into a stationary block of wood having mass m = 5.00 kg. The bullet imbeds…

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Q: In an elastic collision, an object with momentum 25kg•m/s collided with another that has momentum…

A: In an isolated system, the momentum of that system is conserved.

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A:

Q: A 1,500-kg car is traveling due east at 20 m/s when it undergoes a perfectly inelastic collision…

A: Given data: The mass of cars are, m1=1500 kgm2=3000 kg The velocity of cars are, v1=20 m/si^v2=15…