A 2.00-m-tall basketball player is standing on the floor 10.0 mfrom the basket, as in Figure P3.44. If he shoots the ball at a40.0° angle with the horizontal, at what initial speed must hethrow the basketball so that it goes through the hoop withoutstriking the backboard? The height of the basket is 3.05 m.{40.0°3.05 m2.00–10.0 m -Figure P3.44

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Asked Dec 17, 2019
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A 2.00-m-tall basketball player is standing on the floor 10.0 m
from the basket, as in Figure P3.44. If he shoots the ball at a
40.0° angle with the horizontal, at what initial speed must he
throw the basketball so that it goes through the hoop without
striking the backboard? The height of the basket is 3.05 m.
{40.0°
3.05 m
2.00
–10.0 m -
Figure P3.44
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A 2.00-m-tall basketball player is standing on the floor 10.0 m from the basket, as in Figure P3.44. If he shoots the ball at a 40.0° angle with the horizontal, at what initial speed must he throw the basketball so that it goes through the hoop without striking the backboard? The height of the basket is 3.05 m. {40.0° 3.05 m 2.00 –10.0 m - Figure P3.44

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Expert Answer

Step 1

The horizontal and vertical component of initial velocity is

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Vy = v, sin e Vx = v, cose

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Step 2

The horizontal and vertical component of initial velocity is

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x = v_t = (V, cose)t 10m = (v, cos 40°) t 10m [1] Vo (cos40°): 0.

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Step 3

Write the expression for vertical di...

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Ay = v,t + at = (v, sin )t +at 1 2 1 3.05m – 2m = (v, sin 40°)t + –(-9.8m/s? )r² :(-9.8m/s³ )t² 1.05 m = (v, sin 40°)t + - [2]

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