A 2.90 kg object is subjected to three forces that give it an acceleration a = (3.70 m/s? )î + (4.10 m/s² )j. If two of the three forces are F = ( 26.0N )î + ( 16.0N ) and F2 = (12.0N)i + (8.20 N )i, find (a) the x component and (b) the v component of the the third force.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter4: The Laws Of Motion
Section: Chapter Questions
Problem 23P: A bag of cement weighing 325 N hangs in equilibrium from three wires as suggested in Figure P4.23....
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A 2.90 kg object is subjected to three forces that give it an acceleration á = (3.70 m/s? )i + (4.10 m/s² )j. If two of the three forces are
(26.0 N)i + (16.0N)j and F2 = |
(12.0N)i + (8.20 N )i,
F1 =
find (a) the x component and (b) the y component of the the third force.
Transcribed Image Text:A 2.90 kg object is subjected to three forces that give it an acceleration á = (3.70 m/s? )i + (4.10 m/s² )j. If two of the three forces are (26.0 N)i + (16.0N)j and F2 = | (12.0N)i + (8.20 N )i, F1 = find (a) the x component and (b) the y component of the the third force.
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