  # A 23.74-mL volume of 0.0981 M NaOH was used to titrate 25.0 mL of a weak monoprotic acid solution to the stoichiometric point. Determine the molar concentration of the weak acid solution.

Question

A 23.74-mL volume of 0.0981 M NaOH was used to titrate 25.0 mL of a weak monoprotic acid solution to the stoichiometric point. Determine the molar concentration of the weak acid solution.

check_circleExpert Solution
Step 1

When acid reacts with a base, it leads to the formation of salt and water. The chemical reaction for the same is shown as follows:

Step 2

As per the data given in the question,

Volume of NaOH = 23.74 mL = 0.02374 L (As 1 mL = 10-3 L)

Concentration of NaOH = 0.0981 M

Therefore, the number of moles of NaOH will be calculated as follows:

Step 3

According to the chemical reaction mentioned above,

moles of HA = moles of NaOH = 0.002328894 mol

It is given that, volume of HA = 25.0 ...

### Want to see the full answer?

See Solution

#### Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour*

See Solution
*Response times may vary by subject and question
Tagged in

### Chemistry 