Question
Asked Nov 12, 2019
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A 280 Ω resistor and a 600 Ω resistor are in series. When this combination is connected across a 12-V battery, what is current?

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Expert Answer

Step 1

Given,

R 280
R, = 600
V 12 V
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R 280 R, = 600 V 12 V

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Step 2

The resistors are in series, so equivalent resistance,

R.
+
=280+600 Q
=880 Q
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R. + =280+600 Q =880 Q

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Step 3

The current in th...

V = IR
V
I =
12
880
0.01363 Amp
=13.63x 103 Amp
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V = IR V I = 12 880 0.01363 Amp =13.63x 103 Amp

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