A 3.0 kilogram object is placed on a frictionless, 25° incline. Determine the component of the object’s weight that is parallel to the incline. Determine the component of the object’s weight that is perpendicular to the incline.

Q: 1. Refer to figure 1. A wooden block stands motionless on a ramp.. Calculate the coefficient of…

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A: m1 = 1.92 kg m2 = 3.88 kg μs = 0.392 FBD

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A: Given data The first mass is m1=5.7 kg The second mass is m2=3.1 kg The free-body diagram of the…

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A: Force Applied = F = 36 N Weight W = Normal force N = 52 N Coefficient of kinetic friction = μk = ?

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A: Step 1It is given that

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A: Net force is vector sum of all the forces acting on an object

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A: Mass of crate" m "= 345 lb  Coefficient of static friction "us"= 0.25. force to move it let be "F…

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Q: 3. Boxes A and B are in contact on a horizontal, frictionless surface (shown below). Box A has mass…

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Q: A 10.0 kg toboggan slides down a frictionless icy hill with a slope of 25.0 ̊. a) Calculate the…

A: Weight of the toboggan= 10.0 kg Slope= 25⁰

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Q: at is the net force of a 3.0 N force and an 7.0 N force acting on an object for each of the…

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Q: Block A in the figure (Figure 1) weighs 1.21 NN and block B weighs 3.61 NN . The coefficient of…

A: Kinetic friction The kinetic friction is mentioned  as a force of inverse  action among a pair  of…

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Q: Newton's second law of motion states that the force acted on an object is equal to F = m•a. • F…

A: according to the newton's second law,  F=ma

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A: Let the conservative force exerted on an object is represented by F (x,y,z) which means that the…

Q: in the figure (Figure 1) weighs 1.08 N , and block B weighs 3.16 N . The coefficient of kinetic…

A: Given:- Block A in the figure (Figure 1) weighs 1.08 N , and block B weighs 3.16 N . The coefficient…

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Q: A body weighing 200N is just on the point pf moving up the plane by a force of 120N acting parallel…

A: Weight of body =200N Force applied parallel to plane = 120N θ = 15°

Q: box of mass 2 kg is placed on a rough surface that is inclined at an angle of 30 to the horizontal.…

A: m= 2 kg   θ = 30 degree     N= 2 g cos30       we know that friction force  fs = μN  =  μ X 2 Xg cos…

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Q: Suppose an object feels two forces F1 = 5 N & F2 = 7 N (see figure). What will the net force on the…

A: The expression for the net force acting on the object is,

Q: My 5 kg cat wants to push his box of kitty chow off the table so it will spill a snack for his…

A: Given data:  Mass (m) = 1 kg Gravitational force (Fg) = 9.8 N Coefficient of friction (μ) = 0.25…

Q: Which of the following is true regarding Newton's Second Law of Motion? A. Increasing the net force…

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Q: Question. points A force F-200 N acts to pull a fish box of mass 40 kg on a rough horizontal surface…

A: Given Data:  Applied force, F=-200 N Box mass, m=40 kg Friction coefficient, μ=0.25 Standard Data:…

Q: A force is applied to two blocks connected by a massless cable as shown. The coefficients of…

A: Given data The mass of the first block is m1 = 5 kg The coefficient of kinetic friction on the first…

Newton's First Law of Motion

If a very smooth ball is rolled down an inclined surface with zero friction, the ball will continue to roll indefinitely for an infinite time, in an attempt to reach to the same height on the opposite hill!