A 30kV, 50MVA generator having a solidly grounded neutral and Z1 = 0.25pu, Z2=0.15pu and Z0=0.05pu. a. Calculate the fault current and voltages for a single line to ground fault. b. Sketch the phasor diagram for the fault voltages.

A 30kV, 50MVA generator having a solidly grounded neutral and Z1 = 0.25pu, Z2=0.15pu and Z0=0.05pu. a. Calculate the fault current and voltages for a single line to ground fault. b. Sketch the phasor diagram for the fault voltages.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter9: Unsymmetrical Faults

Section: Chapter Questions

Problem 9.31P

See similar textbooks

Related questions

Q: Q2. Explain the symmetrical fault analysis using ZbuS.

A: Note: As per the guidelines will be solving only 1st question. Repost for others Symmetrical fault…

Q: For the following single line diagram of a three-phase system, a three-phase fault occurs at point P…

A: Given data : G1 = 20mvA = 6.9kv which is taken as base value Xg1 = 0.15 pXg2 at new Base =…

Q: A 500-MVA 20-kV, 60-Hz synchronous generator with reactances X, = 0.15, X: 0.24; X 1.1 per unit and…

Q: B-For the radial shown in the figure below, calculate: 1- the fault currents for the faults.: FA and…

Q: Line to line to line fault is an asymmetrical type of fault in power system which occurs very…

A: Given Line to line fault is an asymmetrical type of fault in power system.

Q: The following figure shows the single-line diagram of a three-bus power system. Additionally, a…

A: y23=-j20-j25 =-j45 If three phase fault occurs at bus 3

Q: For the following network, calculate the fault currents (IF1, IF2, IF3 and IF4) in pu and in kA, and…

A: …

Q: For the circuit shown, the normal operating values shown are known. If a symmetrical three-phase…

A: We can redraw the per-phase equivalent circuit as

Q: For the radial power system shown in Figure 3, calculate the line-to-ground fault current flowing in…

A: Apply KVL to find I1.Ps Z42 I1 + Z23 I1 + Z34 I1 – 1(angle 0) = 0 (Z42 + Z23 + Z34) I1 = 1(angle 0)…

Q: Figure 8.26 shows a single-line diagram of a three-phase, interconnected generator- reactor system,…

Q: A 3-phase, 3-wire system has a normal voltage of 10-4 kV between the lines. It is supplied by a…

A: We have 3-phase 3-wire system with, Line Voltage (V) = 10.4 KV Positive reactance (X1) = 0.6 Ω…

Q: Find, for a symmetrical three-phase symmetrical three-phase fault at node 2 the values during the…

A: Motor load rating SM3ϕ=150kVApf=0.8 lagV2ph=3k3VV2ph=1kV Before fault,…

Q: Explain how the value of fault current can be computed for L-L-G fault occurring at the terminals of…

A: Fault current: It is a current that comes into the picture when the fault occurs. The current is the…

Q: Problem 6 a- Explain the reasons for applying system grounding in electric power systems. Consider…

A: The current flowing through a circuit during a fault condition is called fault current. Fault types…

Q: For the system shown below, each generator has positive, negative, and zero sequence reactances of 3…

A: You have asked multiple independent questions. We are authorized to answer one question at a time.…

Q: Figure 2 shows the circuit of a simple power system. The ratings of the generators, transformers and…

A: As per the guidelines of Bartleby we supposed to answer 1st three subparts of the question. For…

Q: I. Draw the reactance diagram for the following power system in per unit using base power = 50 MVA…

Q: 5. The positive sequence network, negative sequence network and zero sequence network are shown in…

A: It is given that: Zf=0.05

Q: For the following single line diagram of a three-phase system, a three-phase fault occurs at point P…

A: The fault occurs at P. Transient reactance of the motor, Xm'(pu)=1.7*0.14 =0.238

Q: The magnitude of the fault current depends on the generator and fault impedance and ________________…

A: The magnitude of fault current depends on voltage at fault point and impedance upto fault point…

Q: The LLLG fault occurs at bus-6 with pre-fault voltage as 1.05 p.u. If the positive sequence…

A: Given, The pre-fault voltage at bus-6 is V6 = 1.05 pu Positive sequence impedance at bus-7 is Z7 =…

Q: A 30MVA, 3-phase, 50HZ 13.8kV, star-connected synchronous generator has positive, negative and zero…

Q: 96\ Derive equations of critical clearing angle and time for a symmetrical three-phase fault at…

Q: fault current

A: Given- Sequence→ Positive Negative Zero Generator 0.16j 0.16j 0.06j Transformer-1 0.1j 0.1j 0…

Q: For the circuit shown, if a symmetrical three-phase fault occurs in node 2, determine a. The…

Q: Critical clearing time of a fault in power system is related to steady state stability limit True…

A: Critical clearing time is the maximum time that is allowed to remove the disturbance without…

Q: It is required to keep L-G fault current with zero fault impedance to rated line current. Determine…

A: In this question we need to find a reactance need to be placed in neutral of genrator to limit the…

Q: a. In sequence networks of power system, why does voltage sources appear only in the positive…

A: a) Machine are design such as it will generate voltage if the phase sequence will be same as…

Q: Thévenin equivalent sequence networks looking into the faulted bus of a power system are given with…

A: Given that z1=0.15 z2=0.15 z0=0.2 Vf=1∠0° (a) For three phase balanced fault Formula for fault…

Q: The one-line diagram of a simple power system is shown in the figure. The neutral of each generator…

Q: When a 40 MVA, 13KV, 3 – phase generator is subjected to a 3 – phase fault, the fault current is j4…

A: The solution is given below

Q: A 3-phase, 3-wire system has a normal voltage of 10-4 kV between the lines. It is supplied by a…

A: We have 3-Phase, 3-Wire system with, Normal Voltage (Vl) = 10.4 KV = 10.4 * 103 V Generator Positive…

Q: For the system shown in figure Q5. а. Determine the three-phase fault power (in MVA) and the short…

A: Base MVA= 20MVA Per unit reactance of all the generators: Per unit reactance of transformers:

Q: A 10 MVA, 6.9 kV alternator has a positive, negative and zero sequence per unit reactance components…

A: In this answer we will find the fault current in the case of a single line - ground fault as…

Q: Given the network shown, for a solid three phase fault on bus 2 (a) find the subtransient current in…

A: The state where the three conductors are physically held together with zero impedance between them,…

Q: In a 3 phase, 3 wire system, it has normal voltage of 10.4kV line to line fault occurs at generator…

A: For the 3- phase line to line the positive sequence phase current is evaluated as:

Q: For the following single line diagram of a three-phase system, a three-phase fault occurs at point P…

A: G1=20 MVA1=6.9 kVis taken as base valueXg1=0.15 pu Xg2(at new base)=0.08×2025×6.96.92…

Q: d) Discuss the procedure for computation of fault current in power system when a double line to…

Q: Q2/The positive-sequence reactances for the power system shown in Figure are in per unit on a common…

A: Given: The positive-sequence reactances for the power system shown in the figure are in per unit on…

Q: A three-phase short circuit occurs at point P for the system shown in the following figure. (a)…

A: In this solution, we'll discuss about pu impedance diagram & fault analysis of a power system.

Q: For the following single line diagram of a three-phase system, a three-phase fault occurs at point P…

A: Given data : G1 = 20mvA = 6.9kv which is taken as base value Xg1 = 0.15 pXg2 at new Base =…

Q: 5.2 Balanced Three-phase Fault Example 5.1 Determine the fault current, the bus voltages, and…

A: When all three lines are shorted to ground, this is known as a balanced (or three phase) fault. It…

Q: Consider a single line to ground fault at the neutral end of a Y-connected stator winding of a…

A: Single line to ground fault-: ER→ = I1→ Z1 + I2 →Z2 + I0→ Z0 + VR where; VR→ = 0I1→ = I2→ = I0→…

Q: For the following single line diagram of a three-phase system, a three-phase fault occurs at point P…

A: Given vales, KVA=20,000 KVA KV=6.9KV Zp.u. of G1=j0.15 p.u.and Zp.u. of G2= 0.08 * SnewSold *…

Q: A three-phase circuit breaker hasa15.5-kV rated maximum voltage, 9.0-kA rated short-circuit current,…

A: a) The three-phase circuit breaker has the maximum voltage =15.5 kV Calculate the minimum voltage:…

Q: Contribution of fault analysis in power system netwrok?

A: Solution- Contribution of fault analysis in power system network- Fault analysis of a power system…

Q: Line to line to line fault is an asymmetrical type of fault in power system which occurs very…

A: Choose the correct option The given Statment Line to line to line fault is an asymmetrical type of…

Q: A three-phase short circuit occurs at point P for the system shown in the following figure. (a)…

A: The most widely recognized kind of short out in a three-stage framework is a single conductor to…

Q: Y-connected, solid grounded and is operated at rated voltage at no-load and is disconnected from the…

Concept explainers

Fault Analysis

In an electrical engineering system, a fault is an abnormal electric current flowing through the system, and fault analysis is the study of these faults. For instance, a short-circuit is a fault where the live wire touches the ground or neutral wire. If a circuit is interrupted by a failure of a current-carrying wire then an open circuit fault occurs. The open-circuit faults are also called series faults. One or more phases or ground may be involved in a three-phase fault or may occur only between two phases. Current flows into the earth in case of a ground fault or earth fault. For most situations, the prospective short circuit current of a fault that is predictable can be calculated. To limit the loss of service because of a failure, the protective devices can detect fault conditions and operate circuit breakers and also other devices. All phases equally can be affected in a poly-phase system which is known as symmetric electrical fault. The asymmetric fault becomes more complicated to analyze if only some phases are affected. By using methods such as symmetrical components, the power system analysis of these types of faults is often simplified. The main objective of power system protection is to design, detect, and interrupt power system faults.

Question

A 30kV, 50MVA generator having a solidly grounded neutral and Z1 = 0.25pu, Z2=0.15pu and
Z0=0.05pu.
a. Calculate the fault current and voltages for a single line to ground fault.
b. Sketch the phasor diagram for the fault voltages.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Equipment ratings for the five-bus power system shown in Figure 7.15 are as follows: Generator G1:Â Â Â Â 50Â MVA,Â 12kV,Â X=0.2 per unit Generator G2: 100Â MVA, 15 kV, X=0.2 per unit Transformer T1: 50 MVA, 10 kV Y/138kVY,X=0.10 per unit Transformer T2: 100 MVA, 15 kV /138kVY,X=0.10 per unit Each 138-kV line: X1=40 A three-phase short circuit occurs at bus 5, where the prefault voltage is 15 kV. Prefault load current is neglected. (a) Draw the positive-sequence reactance diagram in unit on a 100-MVA, 15-kV base in the zone of generator G2. Determine (b) the ThĂ©venin equivalent at the fault, (c) the subtransient fault current in per unit and in kA rms, and (d) contributions to the fault from generator G2 and from transformer T2.
Equipment ratings for the four-bus power system shown in Figure 7.14 are as follows: Generator G1: 500 MVA, 13.8 kV, X=0.20 per unit Generator G2: 750 MVA, 18 kV, X=0.18 per unit Generator G3: 1000 MVA, 20 kV, X=0.17 per unit Transformer T1: 500 MVA, 13.8/500YkV,X=0.12 per unit Transformer T2: 750 MVA, 18/500YkV,X=0.10 per unit Transformer T3: 1000Â MVA, 20/500YkV,X=0.10 per unit A three-phase short circuit occurs at bus 1, where the prefault voltage is 525 kV. Prefault load current is neglected. Draw the positive-sequence reactance diagram in per unit on a 1000-MVA, 20-kV base in the zone of generator G3. Determine (a) the ThĂ©venin reactance in per unit at the fault, (b) the subtransient fault current in per unit and in kA rms, and (c) contributions to the fault current from generator G1 and from line 1-2.
A three-phase circuit breaker has a 15.5-kV rated maximum voltage, 9.0-kA rated short-circuit current, and a 2.50-rated voltage range factor. (a) Determine the symmetrical interrupting capability at 10-kV and 5-kV operating voltages. (b) Can this breaker be safely installed at a three-phase bus where the symmetrical fault current is 10 kA, the operating voltage is 13.8 k V, and the (X/R) ratio is 12?
Consider the oneline diagram of a simple power system shown in Figure 9.20. System data in per-unit on a 100-MVA base are given as follows: The neutral of each generator is grounded through a current-limiting reactor of 0.08333 per unit on a 100-MVA base. All transformer neutrals are solidly grounded. The generators are operating no-load at their rated voltages and rated frequency with their ENIFs in phase. Determine the fault current for a balanced three-phase fault at bus 3 through a fault impedance ZF=0.1 per unit on a 100-MVA base. Neglect -Y phase shifts.
With the same transformer banks as in Problem 3.47, Figure 3.41 shows the oneline diagram of a generator, a step-up transformer bank, a transmission line, a stepown transformer bank, and an impedan load. The generator terminal voltage is 15 kV (line-to-line). (a) Draw the per-phase equivalent circuit, aounting for phase shifts for positive-sequence operation. (b) By choosing the line-to-neutral generator terminal voltage as the reference, determine the magnitudes of the generator current, transmiss ion-line current, load current, and line-to-line load voltage. Also, find the three-phase complex power delivered to the load.
Figure 3.39 shows a oneline diagram of a system in which the three-phase generator is rated 300 MVA, 20 kV with a subtransient reactance of 0.2 per unit and with its neutral grounded through a 0.4- reactor. The transmission line is 64km long with a cries reactance of 0.5-/km. The three-phase transformer T1 is rated 350MVA.230/20kV with a leakage reactance of 0.1 per unit. Transformer T2 is composed of three single-phase transformers, each rated 100 MVA, 127/13.2kV with a leakage reactance of 0.1 per unit. Two 13.2kV motors M1 and M2 with a subtransient reactance of 0.2 per unit for each motor represent the load. M1 has a rated input of 200 MVA with its neutral grounded through a 0.4- current-limiting reactor, M2 has a rated input of 100 MVA with its neutral not connected to ground. Neglect phase shifts associated with the transformers. Choose the generator rating as base in the generator circuit and draw the positive-sequence reactance diagram showing all reactances in per unit.
At the general three-phase bus shown in Figure 9.7(a) of the text, consider a simultaneous single line-to-ground fault on phase a and line-to-line fault between phases b and c, with no fault impedances. Obtain the sequence-network interconnection satisfying the current and voltage constraints.