Question
Asked Oct 2, 2019
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A small block of mass 200 g starts at rest at A, slides
to B where its speed is vB = 8.0 m/s, then slides along the
horizontal surface a distance 10 m before coming to rest
at C. (See below.) (a) What is the work of friction along
the curved surface? (b) What is the coefficient of kinetic
friction along the horizontal surface?

 

А
4.0 m
С
В
10 m-
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А 4.0 m С В 10 m-

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Expert Answer

Step 1

a)

Initially, as the block slides from A to B , it actually loses a height of 4m.

The potential Energy lost by the block when it slides down through a height of 4 m from Point A to point B is converted to Kinetic Energy and Friction.

This can be represented as,

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AP.E AK.E fAB

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Step 2

 

Here fAB is the frictional work done by the block between points A and B, ΔP.E is the change in the potential energy and ΔK.E is the change in the Kinetic Energy.

The change in potential energy and kinetic energy is defined as,

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AP.E mgAh 1 AK.E m 2

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Step 3

Substitute 200g for mass m of the block, 9.8m/s2 for the acceleration due to gravity g, and 4 m for Δh and 8.0 m/s...

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AP.E-200g 1kg 1000g (9.8m/s*)(4m) 7.84J 1kg (8.0m/s) AK.E=200g ΔΚ.Ε 2 6.4J

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